Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.
50. 2x50 = 100. To be safe I would go with any number Between 50 and 100
1.) 14
2.) 10
3.) 7 : 6
5.) 80
6.) 8 : 7
these are all i have the time to answer i'm sorry!
Answer:
Step-by-step explanation:
In a trapazoid the diagonals are the same so therefore the two equations equal echother
3x+7=5x-11 solve for x by combining like terms
18=2x then divide to unto multiplication
9=x
9 is the value of x
I hope I've helped!
