We simply rearrange the equation to find t:
rt = d
t = d/r
If the sum is 5 or more you round it up to the next whole number. If it is less than 5 you keep it at the same whole number
Distribute (2x+y) throughout (4x^2-2xy+y^2). You should get
8x^3-4x^2y+2xy^2+4x^2y-2xy^2+y^3
Simplify and collect like terms and you should get 8x^3+y^3
Answer:
the answer is option b because the sets in option b have an average of two and above
