Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.
Combined Area = (2x + 26)*(2x + 8) = 1008
2x*(2x + 8) + 26*(2x + 8 ) = 1008
4x² + 16x + 52x + 208 = 1008
4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0. Divide through by 4.
x² + 17x - 200 = 0 . This is a quadratic equation.
Multiply first and last coefficients: 1*-200 = -200
We look for two numbers that multiply to give -200, and add to give +17
Those two numbers are 25 and -8.
Check: 25*-8 = -200 25 + -8 = 17
We replace the middle term of +17x in the quadratic expression with 25x -8x
x² +17x - 200 = 0
x² + 25x - 8x - 200 = 0
x(x + 25) - 8(x + 25) = 0
(x+25)(x -8) = 0
x + 25 = 0 or x - 8 = 0
x = 0 -25 x = 0 + 8
x = -25 x = 8
The width of the path can not be negative.
The only valid solution is x = 8.
The width of the path is 8 meters.
Answer:
Move the point on the diagonal to (1,4) then move the vertex 4 units left and 3 units upwards
Step-by-step explanation:
Answer:
115 m
Step-by-step explanation:
4 + 9 + 6 + 4 = 23 cm
23 x 5 = 115 m
Answer:
4.4 L
Step-by-step explanation:
Given:
Water required for every 2 miles = 1 quart
Total distance traveled = 15 km
Now,
1 km = 0.621 miles
thus,
15 km = 0.621 × 15 = 9.32 miles
Therefore,
Quarts of water required for 15 km (9.32 miles) = 
= 4.66 quarts
also,
1 quart = 0.95 L
therefore,
4.66 quarts = 4.66 × 0.95 = 4.427 ≈ 4.4 L
