...require a living host cell to survive.
The answer is A. <span>effective length of the tube
In wind instrument, the effective length is not the actual length of the instrument but only the length that the finger holes manage to cover.
The more holes it managed to cover, the higher frequency of vibration it might able to produce, which lead to higher pitch of the instrument.</span>
Answer:
given, mother and father are heterozygotes.
let, father has B blood group and mother has A blood group.
then their heterozygous genotypes are --
father = iB, iO and mother = iA, iO
punnett square will be,
iB iO
iA iA iB iA iO
iO iB iO iO iO
the genotypes of their progeny will be, iAiB , iAiO ,iBiO and iOiO
and phenotypes will be 3 are heterozygous and 1 is homozygous.
Answer:
I think the answer is likely A
