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GenaCL600 [577]
3 years ago
9

Item 9 a softball has a volume of 1256π1256π cubic inches. find the radius of the softball.

Mathematics
1 answer:
TEA [102]3 years ago
5 0
\boxed{\boxed{\text{Volume = } \dfrac{4}{3} \pi r^3}}

Given that volume = 1256π, find radius:

1256 \pi = \dfrac{4}{3} \pi r^3

r^3 = 1256 \pi \div\dfrac{4}{3} \pi

r^3 = 942

r= \sqrt[3]{942}

r = 9.8 \text{ inches (nearest hundredth)}

Answer: The radius is 9.8 inches.
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Ratios are basically fractions, and can simplify as such. 2:54 = 2/54. Just simplify by dividing 2 by 54. (2 / 54 ~~ 1/27) Turn into rate. 1/27 = 1:27.


Thus, 1:27 is the answer.

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What is the missing term in this geometric table?
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72 = 7 x 7 = 49 i need an answer for this question
Murrr4er [49]

Answer:

72=7×^7 -49

Step-by-step explanation:

3 0
3 years ago
Anyone can help me to solve this?​
marishachu [46]

Answer:

x^3+3x^2+2x

Step-by-step explanation:

<u>Definitions</u>

Integer: A whole number that can be positive, negative, or zero.

Consecutive Integers: Integers that follow each other continuously in the order from smallest to largest.

Product: The result of multiplying two of more values together.

Let x be the first integer.

Therefore, to find the consecutive integers, add 1 to each term:

  • x
  • x + 1
  • (x + 1) + 1 = x + 2

Therefore, the product of the first three consecutive integers is:

\begin{aligned}x(x+1)(x+2) & = (x \cdot x+x \cdot 1)(x+2)\\& = (x^2+x)(x+2)\\ & = x^2 \cdot x+x^2 \cdot 2+x \cdot x+x \cdot 2\\& = x^3+2x^2+x^2+2x\\& = x^3+3x^2+2x\end{aligned}

6 0
1 year ago
Read 2 more answers
Could you please help for this?<br> Please.
Serggg [28]

Answer:

CD = 6.385 units

Step-by-step explanation:

Given triangle ABC with right angle at C.

And AB = AD + 6 .

Now, consider the triangle ABC.

⇒ cos(∠BAC) = \frac{AC}{AB}  (cosФ = adj/hyp)

cos(20) = \frac{AC}{AB} .

0.9397 = \frac{AD+CD}{AD + 6}

(since AB = AD + 6 and AC = AD + CD)

⇒ 0.9397 AD + 5.6382 = AD + CD

⇒ CD = 0.0603 AD + 5.6382. →→→→→ (1)

⇒ sin(∠BAC) =  \frac{BC}{AB} (sinФ = opp/hyp)

sin(20) =  \frac{BC}{AB}.

⇒ BC = AB sin(20)  . →→→→→(2)

Now, consider the triangle BCD,

sin(∠BDC) =  \frac{BC}{CD}

⇒ sin(80) =  \frac{BC}{CD}

CD =  \frac{BC}{sin(80)}

From (2), CD = \frac{AB sin(20)}{sin(80)} .

⇒ CD = AB (0.3473)

⇒ CD = (AD + 6) (0.3473)

⇒ CD = 0.3473 AD + 2.0838 →→→→→→(3)

Now, (1) →→ CD = 0.0603 AD + 5.6382

         (3) →→ CD = 0.3473 AD + 2.0838

⇒ 0.0603 AD + 5.6382 = 0.3473 AD + 2.0838

0.287 AD = 3.5544.

⇒ AD = 12.3847

⇒ From (1), CD = 0.0603(12.3847) + 5.6382

⇒ CD = 6.385 units

7 0
4 years ago
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