Answer:
<h2>h = 4 cm</h2><h2 />
Step-by-step explanation:
V = π r² h
where r = 3 cm
V = 36π cm³
solve for h
plugin values into the formula:
36π = π 3² h
h = <u> 36π </u>
π 3²
h = 4 cm
Answer:
Solving the given linear system, we get x = 1 and y = -3.
The solution set is: (1,-3)
Step-by-step explanation:
We need to solve the linear system of equations.

We can write second equation y=x-4 as: 
Let:

Now, Adding equation 1 and 2

So, we get x = 1
Now, put value of x in second equation to find value of y:

So, we get y = -3
Solving the given linear system, we get x = 1 and y = -3.
The solution set is: (1,-3)
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Step-by-step explanation:
10. |-41|= 41
12. -|1.5|= -1.5