The photos are in the wrong way :(
This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
The answer would be x + x + 2 = 72. Combine like terms so that 2x + 2 = 72. 2x = 70 and x = 35.
2. Look at which density value has the most samples, or which value has the most x's.
3. Look at the greatest density recorded and the lowest density recorded. What is the difference between these two densities? For example, if 1 and 3 were the lowest and greatest densities the answer would be 2.
Answer:
136/2 = 68
Step-by-step explanation:
8 x 8 = 64 and
12 x 6 = 72
72 + 64 = 136
