All categories

3 years ago

HELP FASTTTTTTTTTTTT

Mathematics

2 answers:

Nuetrik [128]3 years ago

8 0

Answer:

x = 1 (blue line)

Step-by-step explanation:

The points that dont move are the ones on the line of reflection, here (1, 1) and (1, 4) are on the line and stay the same.

If you had reflected it using the red line, only (1, 1) would have stayed the same

Alex3 years ago

3 0

Answer:

Blue line.

Step-by-step explanation:

Two of the points are on the blue line, so only the other two would be reflected over it.

You might be interested in

A piece of wire 19 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

mr Goodwill [35]

Answer: 8.26 m

Step-by-step explanation:

$Let s be the length of the wire used for the square. \\Let $t$ be the length of the wire used for the triangle. \\Let $A_{S}$ be the area of the square. \\Let ${A}_{T}}$ be the area of the triangle. \\One side of the square is $\frac{s}{4}$ \\Therefore,we know that,$$A_{S}=\left(\frac{s}{4}\right)^{2}=\frac{s^{2}}{16}$

$The formula for the area of an equilateral triangle is, $A=\frac{\sqrt{3}}{4} a^{2}$ where $a$ is the length of one side,And one side of our triangle is $\frac{t}{3}$So,We know that,$$A_{T}=\frac{\sqrt{3}}{4}\left(\frac{t}{3}\right)^{2}$$We have to find the value of "s" such that,$\mathrm{s}+\mathrm{t}=19$ hence, $\mathrm{t}=19-\mathrm{s}$And$$A_{S}+A_{T}=A_{S+T}$

$$$Therefore,$$\begin{aligned}&A_{T}=\frac{\sqrt{3}}{4}\left(\frac{(19-s)}{3}\right)^{2}=\frac{\sqrt{3}(19-s)^{2}}{36} \\&A_{T+S}=\frac{s^{2}}{16}+\frac{\sqrt{3}(19-s)^{2}}{36}\end{aligned}$

$Differentiating the above equation with respect to s we get,$$A^{\prime}{ }_{T+S}=\frac{s}{8}-\frac{\sqrt{3}(19-s)}{18}$$Now we solve $A_{S+T}^{\prime}=0$$$\begin{aligned}&\Rightarrow \frac{s}{8}-\frac{\sqrt{3}(19-s)}{18}=0 \\&\Rightarrow \frac{s}{8}=\frac{\sqrt{3}(19-s)}{18}\end{aligned}$$Cross multiply,$$\begin{aligned}&18 s=8 \sqrt{3}(19-s) \\&18 s=152 \sqrt{3}-8 \sqrt{3} s \\&(18+8 \sqrt{3}) s=152 \sqrt{3} \\&s=\frac{152 \sqrt{3}}{(18+8 \sqrt{3})} \approx 8.26\end{aligned}$

$The domain of $s$ is $[0,19]$.So the endpoints are 0 and 19$$\begin{aligned}&A_{T+S}(0)=\frac{0^{2}}{16}+\frac{\sqrt{3}(19-0)^{2}}{36} \approx 17.36 \\&A_{T+S}(8.26)=\frac{8.26^{2}}{16}+\frac{\sqrt{3}(19-8.26)^{2}}{36} \approx 9.81 \\&A_{T+S}(19)=\frac{19^{2}}{16}+\frac{\sqrt{3}(19-19)^{2}}{36}=22.56\end{aligned}$

$$$Therefore, for the minimum area, $8.26 \mathrm{~m}$ should be used for the square$

8 0

2 years ago

Suppose M is the midpoint of FG. Find the missing measure.<br> MG = 13x + 1, FG = 15

Sholpan [36]

Answer:

14 - 13x

Step-by-step explanation:

take 13x + 1 away from 15

15 - (13x + 1) = 15 - 13x - 1 = 14 - 13x

4 0

3 years ago

HELP ASAP WITH THESE QUESTIONS

tensa zangetsu [6.8K]

The dependent variable is f(m)...total money earned per day
the independent variable is m...number of miles

f(m) = 3.5m + 65

for 40 miles..
f(40) = 3.5(40) + 65
= 140 + 65
= 205 <== money earned for the day
========================
the dependent variable is f(p)....total charged
the independent variable is p...the number of pounds

f(p) = 3.5p

for 5 lbs...
f(5) = 3.5(5)
f(5) = 17.50 <== total that was charged

8 0

4 years ago

Scarlett made 36 muffins on Tuesday, and 20 of the muffins were blueberry. What is the ratio of blueberry muffins to all muffins

Paha777 [63]

Answer:I belive it is 56 I may be wrong but it iz what it iz

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the eqation of the line that satifies the given conditions

aleksklad [387]

The answer is :
C. y = 5x - 10