4 years ago

Define "Image."

1 answer:

8 0

It’s “A figure after it is transformed” because “a figure before it is transformed” would be a pre-image therefore... :)

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Find the sum and product of the roots. 2x^2 + 6x - 8 = 0

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which means in this case, you have to have

$\begin{cases}6=-2(r_1+r_2)\\-8=2r_1r_2\end{cases}\implies\begin{cases}r_1+r_2=-3\\r_1r_2=-4\end{cases}$

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|2x + 1| - 4 < 5 <br><br> solve and graph

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