<em>B</em><em>i</em><em>n</em><em>d</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>e</em><em>x</em><em>p</em><em>r</em><em>e</em><em>s</em><em>s</em><em>i</em><em>o</em><em>n</em><em> </em><em>w</em><em>i</em><em>t</em><em>h</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>m</em><em>m</em><em>o</em><em>n</em><em> </em><em>f</em><em>a</em><em>c</em><em>t</em><em>o</em><em>r</em><em> </em><em>-</em><em>4</em>
<h3>#❀CARRY ON LEARNING❀</h3><h3>#❀KEEP ON LEARNING❀</h3><h3>#❀LEARNING IS FUN❀</h3><h3>#❀LETS LEARN❀</h3><h3>#❀NoToCopyPaste❀</h3><h3 /><h3>❀hope it helps(◕ᴗ◕✿)❀</h3><h3>❀Keep safe!❀シ︎</h3>
Answer:
a would be 12
Step-by-step explanation:
because there are 5 1's so you would subtract 5 from 65 and get 60 and divide 60 by 5 and get 12
Hope this helps!!! Mark me as brainiest!!!!! :)
Answer:
true ...
believe it or not there is an exponential sequence that can make that
result
f(x) =
<u>x /// 2(x+2) -1</u>
-1 /// 1
0 /// 3
1 /// 5
2 /// 7
Step-by-step explanation:
Answer:
x−2x4+2x3−7x2−8x+12=x3+4x2+x−6
The rational root theorem suggests that other possible roots may be -6, 6, -3, 3, -2, 2, -1, and 1. It turns out that x=-2x=−2 is a root, since (-2)^3+4(-2)^2+(-2)-6=0(−2)3+4(−2)2+(−2)−6=0 , so x+2x+2 is also a factor and we have
\dfrac{x^4+2x^3-7x^2-8x+12}{(x-2)(x+2)}=x^2+2x-3(x−2)(x+2)x4+2x3−7x2−8x+12=x2+2x−3
Finally, we can factorize the remaining quotient easily:
x^2+2x-3=(x+3)(x-1)x2+2x−3=(x+3)(x−1)
so the other factors are x+2x+2 , x+3x+3 , and x-1x−1 .