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denis-greek [22]
4 years ago
12

Kim's softball team was playing in the championship game. When there were 4 innings left, the team was losing by a score of 17 t

o 6 points. In the last 4 innings, her team scored the same number of points per inning, and the other team did not score any more points. Kim's team won with the most points.
Write an inequality to determine the number of points per inning, ppp, Kim's team could have scored.
Mathematics
1 answer:
Ulleksa [173]4 years ago
3 0

Answer:

The required inequality is 6+4p>17.

Step-by-step explanation:

Let p represent the number of runs per inning.

It is given that the team scores the same number of runs per inning and the other team did not score any more points. So, the total score of other team after last four inning is 17.

Kim's team total score in last four inning is 4p. So, the total score of Kim's team after last four inning is

6+4p

Kim's team win if the total score of other team after last four inning is less than the Kim's team.

6+4p>17

Therefore the required inequality is 6+4p>17.

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An F5 tornado is classified as having mean wind speeds greater than 261 mph. In an effort to classify a recent tornado, 20 wind
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Complete Question

An F5 tornado is classified as having mean wind speeds greater than 261 mph. In an effort to classify a recent tornado, 20 wind speed measurements were randomly selected from within the path of the tornado. Suppose the mean wind speed for this tornado really is greater than 261 mph with a sample standard Deviation 41.09 mph. Based on the data, if we fined little to no evidence against the null hypothesis that the mean wind speed is 261 mph, we have made _______________.

Answer:

P-value=0.3322

Step-by-step explanation:

From the question we are told that:

Sample size n=20

Population mean N=261  

Sample mean \=x= 265.1  

Sample standard deviation \sigma=41.09    

Generally the equation t test statistics is mathematically given by

t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }

t=\frac{265.1-261}{\frac{41.09}{\sqrt{20} } }

t=0.446

Therefore

Pvalue from table is

P-value=0.3322

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