Answer:
λ = 37 nm
Radiation is in the ultra violet region.
Explanation:
Given data:
Energy of photon = 5.44 × 10 ⁻¹⁸ J
Wavelength of photon = ?
Solution:
E = h.c / λ
λ = h. c/ E
λ = 6.63× 10⁻³⁴m² kg/s × 3×10⁸ m/s / 5.44 × 10 ⁻¹⁸ Kg m²/s²
λ = 19.89 × 10⁻²⁶ kg. m³ /s² / 5.44 × 10 ⁻¹⁸ Kg m²/s²
λ = 3.7 × 10⁻⁸ m
m to nm conversion.
λ = 3.7 × 10⁻⁸m ×10⁹ nm / 1m
λ = 37 nm
Radiation is in the ultra violet region because the rage of UV is 1 nm - 400 nm.
In addition to water and carbon dioxide, photosynthesis requires l<span>ight and chlorophyll. The correct option among all the options that are given in the question is the first option or option "A". The other options can be negated. I hope that this is the answer that has come to your great help.</span>
Answer:
C
Explanation:
This is a monohybrid cross between involving a gene coding for earlobe. The allele for free earlobe (F) is dominant over that of attached earlobe (f).
N.B: let F represent the gene involved.
A genotypic ratio is the ratio derived from the offsprings based on the actual genetic make-up and not based on their phenotypic appearance as in phenotypic ratio.
A homozygous individual is an individual having the same kind of alleles for a gene while a heterozygous individual is one that has two different alleles i.e. combination of the dominant and recessive allele.
The monohybrid cross is between an individual with attached earlobe (ff) i.e. homozygous recessive individual. (Note that, a recessive trait will only be expressed in a homozygous state) and a heterozygous free earlobeb individual (Ff). (See attached picture). Ff × ff
The resulting four offsprings will
be expected to have only two distinct genotypes i.e heterozygous (Ff) and homozygous recessive (ff) in an equal ratio i.e. 2:2 ~ 1:1
I would describe it as being very inconsiderate and wasteful.
Normally during droughts, you should take 3-5 minute showers.
~CoCo