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Lemur [1.5K]
3 years ago
8

Simplify (4x^4y^3)^3/3(5x^2y^6)^2

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer: Hence, our simplified form will be :

\frac{64}{75}x^8y^{-3}

Step-by-step explanation:

Since we have given that

\frac{(4x^4y^3)^3}{3(5x^2y^6)^2}

We need to simplify the above expression:

\frac{(4x^4y^3)^3}{3(5x^2y^6)^2}\\\\=\frac{4^3x^{4\times 3}y^{3\times 3}}{3\times 5^2x^{2\times 2}y^{6\times 2}}\\\\=\frac{64x^{12}y^9}{3\times 25x^4y^{12}}\\\\=\frac{64x^{12}y^9}{75x^4y^{12}}\\\\=\frac{64}{75}x^{12-4}y^{9-12}\\\\=\frac{64}{75}x^8y^{-3}

Hence, our simplified form will be :

\frac{64}{75}x^8y^{-3}

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Answer:

Hence the function which has the smallest minimum is: h(x)

Step-by-step explanation:

We are given function f(x) as:

  • f(x) = −4 sin(x − 0.5) + 11

We know that the minimum value attained by the sine function is -1 and the maximum value attained by sine function is 1.

so the function f(x) receives the minimum value when sine function attains the maximum value since the term of sine function is subtracted.

Hence, the minimum value of f(x) is: 11-4=7 ( when sine function is equal to 1)

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Hence, the minimum value attained by h(x) is 5. ( when x=1)

  • Also we are given function g(x) ; a quadratic function passing through (2,7),(3,6) and (4,7)

so, the equation will be:

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