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Nikolay [14]
3 years ago
14

In a certain​ year, the average​ e-mail user sent or received 162 e-mails each day. the number of​ e-mails received was 66 more

than twice the number sent. how many were sent and how many were received each​ day?
Mathematics
1 answer:
Fantom [35]3 years ago
7 0
Let the number sent = nLet the number received = 66n + 2  Set up an equation using the variables and info given. n + 66n + 2 = 16267n + 2 = 16267n = 160  n = 2.38 or 3Substitute this value of n into the variables.66n + 2 = 1626(3) + 2 = 140= 20 3 emails were sent.20 emails were received
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Find the next 3 terms in each sequence <br> 1). 8, 24, 72, 216.... ____, ______, _____,
allochka39001 [22]

Answer: 648, 1,944, and 5,832.

Step-by-step explanation: Begin by studying the pattern.

Here, notice that 8 × 3 is equal to 24.

24 × 3 is equa to 72.

72 × 3 is equal to 216.

Continuing the same pattern, 216 × 3 is equal to 648.

648 × 3 is equal to 1,944.

1,944 × 3 is equal to 5,832.

I have also attached in image below showing my work.

So the three missing terms in the pattern are <em>648</em>, <em>1,944</em>, and <em>5,832</em>.

7 0
4 years ago
(w15/w5)^4 Simplify it.
Stells [14]

Solution, \left(\frac{w^{15}}{w^5}\right)^4=w^{40}

Steps:

\left(\frac{w^{15}}{w^5}\right)^4

\frac{w^{15}}{w^5}=w^{10}, =\left(w^{10}\right)^4

\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}, =w^{10\cdot \:4}

\mathrm{Refine}=w^{40}

\mathrm{The\:Correct\:Answer\:is\:w^4^0}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

8 0
3 years ago
Read 2 more answers
Find f(4) when f(x) = 5x^2 - 5x + 7.<br><br> A) 107<br> B) 53<br> C) 67<br> D) 3
saul85 [17]

Answer:

the answer is e, obviously

Step-by-step explanation:

7 0
3 years ago
Consider M, N, and P. collinear points on MP.
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}

2. Point N lies to the right from point P, then MP + PN = MN.  Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

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3 0
3 years ago
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