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tekilochka [14]
3 years ago
8

Factor x^8-26x^4+25=0

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0
The answer is (x^4-1)(x^4-25)
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Which of the systems of equations below is equivalent to the system shown?
amm1812

Answer:

D.....is\:   the \: equivalent \: system

Step-by-step explanation:

if \to 4x + 5y = 3 \\ if  \to 2x + 3y = 1 \\then \\ 2 \times  \: 4x + 5y = 3 \\ 4 \times 2x + 3y = 1 \\ 10y - 12y = 6 - 4 \\  - 2y = 2 \\ \boxed{ y =  - 1} \\ 4x  +  5y = 3 \\ 4x  +5( - 1) = 3 \\ 4x  -  5 = 3 \\ 4x = 3  + 5 \\ 4x =  8 \\  \boxed{x =  2} \\ hence \: the \: equivalent \: system \: is \to D \\

7 0
2 years ago
There are 28 students in Sharon's class. One-fourth of the students were absent on Monday. How many students were present on Mon
PIT_PIT [208]

21 students

You find this by subtracting the number of students absent from the total amount of students in the class 28-(28*\frac{1}{4} )=21.

8 0
2 years ago
Read 2 more answers
4(g-1)=24 showing work
algol [13]

Answer:

g=7

Step-by-step explanation:

4(g-1)=24

g-1=6

g=6+1

g=7

3 0
3 years ago
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A checkers board is eight squares long and eight squares wide. The area of each square is 14 cm². Estimate the perimeter of the
Tamiku [17]

Answer:

Perimeter of the board is 119.7 cm.

Step-by-step explanation:

We are given that,

Area of each square = 14 cm²

i.e. Side^2=14

i.e. Side= \sqrt{14}

i.e Side = 3.74 cm

So, we get the side of each square is 3.74 cm.

Since, Perimeter of a square = 4a

→ Perimeter of each square = 4\times 3.74

→ Perimeter of each square = 14.96 cm

<em>Since, there are 8×8= 64 squares on the board.</em>

Thus, the perimeter of the board = 8 × Perimeter of each square.

i.e. Perimeter of the board = 8 × 14.96

i.e. Perimeter of the board = 119.68 cm

Hence, the perimeter of the board rounded to the tenths is 119.7 cm.

4 0
2 years ago
I need help with this i cant cuaet understand it well.​
skelet666 [1.2K]

Answer & Step-by-step explanation:

C = 2πr

3) 2π(53) ≈ 197.9

4) 2π(35) ≈ 219.9

5) 2π(21.5) ≈ 135

I'll let you formulate the last one :)

7 0
2 years ago
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