Malcolm bought dog-food bowls to give away as prizes at a dog-lovers event. The plastic bowls cost 6 dollars each and the stainl
1 answer:
Answer
9 stainless steel bowls
Solution
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What we know:
<span>Malcolm bought 7 plastic bowls and spent a total of 136.50 dollars on prizes
------------------------------------------</span>-------------------------------------------------------------<span>
We would subtract:
136.50 - 42 = 94.5
</span>-------------------------------------------------------------------------------------------------------<span>
After determining the price of the stainless steel bowls, we would then divide:
</span>
-------------------------------------------------------------------------------------------------------
9 stainless steel bowls
Solution
-------------------------------------------------------------------------------------------------------
What we know:
<span>Malcolm bought 7 plastic bowls and spent a total of 136.50 dollars on prizes
------------------------------------------</span>-------------------------------------------------------------<span>
We would subtract:
136.50 - 42 = 94.5
</span>-------------------------------------------------------------------------------------------------------<span>
After determining the price of the stainless steel bowls, we would then divide:
</span>
-------------------------------------------------------------------------------------------------------
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Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation = = 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:
For z = -1.56, we get:
For z = -0.88, we get:
Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)