Integrate indefinite integral:

Solution:
1. use substitution
=>

=>

=>

=>


2. decompose into partial fractions


where A=1/2, B=1/2, C=-1

3. Substitute partial fractions and continue


4. back-substitute u=e^x


Note: log(x) stands for natural log, and NOT log10(x)
Answer:
Sum of 2 no. 120
Let second no. be x
Therefore, first no. =x+5
Therrfore,third no. =3x
Thetefore,x+5+x+3x=120
5x+5=120
5x=115
x=23.
Therefore, 1st no.=28
Second=23
and third=69
Answer:
See Explanation
Step-by-step explanation:
Given



Required
Represent them on number line
Start by getting the LCM of the denominators of the three fractions;
The denominator are: 3 and 5

This means that, the number line will be divided into 15 partitions;
Next, we get the position of each fraction as follows;



<em>Jean will be represented on the 10th point</em>



<em></em>
<em>Terry will be represented on the 5th point</em>
<em></em>



<em>Steve will be represented on the 3rd point</em>
<em></em>
<em>See Attachment for number line</em>
Answer:
do 10 20 20 40 50
Step-by-step explanation:
hope it helps sorry if it does not if not then try 1 2 3 4 5