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nevsk [136]
4 years ago
13

Helppppp pleaseeeeeeeee

Mathematics
2 answers:
sweet [91]4 years ago
7 0
False, because if you do the grouping method, it would be (x+8) (x - 4).
Verdich [7]4 years ago
6 0
False, when you factor out the (x+8) you only present it once.

(x+8)(x-4)
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6 more than thrice a number is 36
posledela
3n+6=36
Hope this helps
7 0
3 years ago
– 18q+10q+16q–3= – 19
sergeinik [125]

Step-by-step explanation:

  • – 18q+10q+16q–3= – 19
  • 8q=-19
  • q=-19/8
  • q=-2.375

8 0
3 years ago
Read 2 more answers
David bought 26 box of crayons for 38.48 how much did he pay for each box of crayons?
kotykmax [81]

1.48 because 38.48÷26 is 1.48

6 0
3 years ago
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Algebraically show that each of the given combinations are equivalent to the given functions. f(x) – g() is
Charra [1.4K]

Answer:

f(x) - g(x) = 2x + 12

m(x) = f(x) - g(x) --- True

Step-by-step explanation:

Given

f(x) = -3x + 5

g(x) = -5x - 7

m(x) = 2x + 12

Solving (a): f(x) - g(x)

From the given parameters, we have:

f(x) = -3x + 5

g(x) = -5x - 7

So:

f(x) - g(x)=-3x+5 + 5x + 7

Collect like terms

f(x) - g(x) = 2x + 12

Solving (b) m(x) = f(x) = g(x)?

In (a), we have:

f(x) - g(x) = 2x + 12

And

m(x) = 2x + 12 --- given

By comparison:

m(x) = f(x) - g(x)

8 0
3 years ago
The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 10^7 kilometers, and the distance of planet Venus from the Su
ziro4ka [17]
Distance(Mercury, Sun) = 5.8 x 10^7
distance(Venus, Sun) = 1.1 x 10^8

distance(Venus, Mars) = 1.1 x 10^8 - 5.8 x 10^7

The subtraction is a little easier if you borrow a power of 10 from the 10^8, multiplying 1.1 by 10.

\rm 11.0\times10^7-5.8\times10^7

simply subtract 5.8 from 11.0.
This gives us a result of 5.2 x 10^7.

Hope that makes sense!
8 0
3 years ago
Read 2 more answers
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