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3 years ago

If david run 3 times he covers a distance of __ yards

Mathematics

2 answers:

grigory [225]3 years ago

6 0

But how many feet is he running each time?

Andre45 [30]3 years ago

3 0

How many miles or inches is the place that he ran 3 times?

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Y= -3x^2-24x-46 write in vertex form

mario62 [17]

ANSWER

$y= -3{(x + 4)}^{2} + 2$

EXPLANATION

The given function is:

$y= -3x^2-24x-46$

Factor -3 for the first 2 terms.

$y= -3(x^2 + 8x)-46$

We add and subtract the square of the coefficient of x.

$y= -3(x^2 + 8x + {(4)}^{2} ) - - 3( {4)}^{2} -46$

Factor the perfect square trinomial.

$y= -3 {(x + 4)}^{2} ) + 48 -46$

The vertex form is:

$y= -3{(x + 4)}^{2} + 2$

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3 years ago

What is equivalent to 12(3+m)

blondinia [14]

Answer:

36 + 12m

Look at attachment

5 0

3 years ago

Read 2 more answers

Brian compared the absolute values of the numbers−12,34,and−14.Arrange the numbers from least to greatest.

solniwko [45]

Answer:

-12, -14, 34

Step-by-step explanation:

3 0

3 years ago

What is the total amount of fees if there were 6 withdrawals for cash in a month, 10 uses of an ATM,

almond37 [142]

Answer:

Step-by-step explanation:

16+10+6=34

3 0

2 years ago

The number of people , d, in thousands applying for medical benefits per week in a particular city can be modules by the equatio

Mekhanik [1.2K]

Answer:

<h2>4773 peoples.</h2>

Step-by-step explanation:

Given the number of people d, in thousands applying for medical benefits per week in a particular city c modeled by the equation d(t)=2.5 sin(0.76t+0.3)+3.8 where t is the time in years, the maximum number of people tat will apply will occur at d(t)/dt = 0

Differentiating the function given with respect to t, we will have;

$d(t)=2.5 sin(0.76t+0.3)+3.8$

First we need to know that differential of any constant is zero.

$Using\ chain\ rule\\\frac{d(t)}{dt} = 2.5cos(0.76t+0.3) * 0.76 + 0\\ \\\frac{d(t)}{dt} = 1.9cos(0.76t+0.3)$

If $\frac{d(t)}{dt} =0$ then;

$1.9cos(0.76t+0.3) = 0\\\\cos(0.76t+0.3) = 0\\\\0.76t+0.3 = cos^{-1} 0\\\\0.76+3t = 90\\\\3t = 90-0.76\\3t = 89.24\\\\t = 89.24/3\\\\t = 29.75years$

To know the maximum number of people in thousands that apply for benefits per year in the city, we wil substitute the value of t = 29.75 into the modeled equation

$d(t)=2.5 sin(0.76t+0.3)+3.8\\d(29.75) = 2.5 sin(0.76(29.75)+0.3)+3.8\\d(29.75) = 2.5 sin(22.61+0.3)+3.8\\\\d(29.75) = 2.5 sin(22.91)+3.8\\\\d(29.75) = 0.9732+3.8\\d(29.75) = 4.7732\\\\$

Since d is in thousands, the maximum number of people in thousands will be 4.7732*1000 = 4773.2 which is approximately 4773 peoples.

3 0

3 years ago