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3 years ago

Using a straightedge, or using technology, sketch an obtuse, scalene triangle. Make sure to include your sketch in your answer.

Mathematics

1 answer:

zubka84 [21]3 years ago

8 0

Obtuse angles measure more than 90 degrees, scalene angles have three different side lengths. Would you like for me to include angle measure in the sketch?

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Please help and show work!!

serious [3.7K]

17.

x = -2 is not a solution of -1 < x < 5 because -2 < -1 (-1 < -2 < 5 FALSE).

18.

m = 5 is a solution of 5 ≤ m because 5 ≤ 5 ( 5 ≤ m → m ≥ 5 greater than 5 or equal 5, 5 is equal 5)

19.

k = 10 is not solution of 2k - 3 < 1 because:

put the value of k to the inequality:

2(10) - 3 < 1

20 - 3 < 1

17 < 1 FALSE

5 0

3 years ago

A day can be evenly divided into 86,400 periods of 1 second; 43,200 periods of each 2 seconds; or in many other ways. In total,

Leni [432]

Answer:

96 ways

Step-by-step explanation:

Given

$Day = 86400\ seconds$

Required

Ways to divide it into period of seconds

What this question implies is to determine the total number of factors of 86400

To start with, we determine the prime factorization of 86400

To do this, we continually divide 86400 by 2; when it can not be further divided, we divide by 3, then 7, then 11...

$86400/2 = 43200$

$43200/2=21600$

$21600/2=10800$

$10800/2=5400$

$5400/2= 2700$

$2700/2 = 1350$

$1350/2=675$

$675/3=225$

$225/3=75$

$75/3=25$

$25/5=5$

$5/5 = 1$

This implies that:

$86400 = 2^7 * 3^3 * 5^2$

The number of factors d is the solved by:

$d = (a+1)*(b+1) *(c+1)$

Where

$n = 2^a * 3^b * 5^c$

By comparison:

$a = 7$

$b = 3$

$c=2$

So:

$d = (7+1)*(3+1) *(2+1)$

$d = 8*4 *3$

$d = 96$

<em>Hence, there are 96 total ways</em>

7 0

3 years ago

Please help this is due at 11

ollegr [7]

me at 1:36pm: oh no, i hope he got his answer

8 0

3 years ago

173 out of 400 pages what is the percent he read

Lubov Fominskaja [6]

173/400 pages of the percentage

6 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago