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goldfiish [28.3K]
3 years ago
13

Please give me the answer and explain

Mathematics
1 answer:
Ahat [919]3 years ago
5 0

Answer:

Brownie is 80 times thicker than cookie.

Step-by-step explanation:

Thickness of brownie is 4 x 10∧-2 feet

Thickness of cookies is 5 x 10∧ -4 feet

Ratio = (4 x 10∧-2)/(5 x 10∧ -4) =80

Brownie is 80 times thicker than cookie.

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A barbecue sold 26 hamburgers and hot dogs. Hamburgers sell for $3.50 each and hot dogs sell for $2.00 each. If the barbecue mad
Angelina_Jolie [31]

x => Hamburgers

y => Hot dogs


x + y = 26

3.5x + 2y = 70


-2x - 2y = -52

3.5x + 2y = 70

-----------------------

1.5x = 18

x = 18 / 1.5 = 12

y = 26 - 12 = 14


They sold 12 hamburgers and 14 hot dogs

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Find the value of x, given the radius. PLEASE HELP IM THID IS TIMED (MOST BRAINLIEST IF YOU ANSWER)
julia-pushkina [17]

Answer:

What is it asking for like the area or just the length the length is 8 if that's what it's asking for because the radius is 15 which makes the diameter 30 and 15 + 7 = 22 30-22 =8

Step-by-step explanation:

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3 years ago
Which type of graph would be best for showing how the population of a country changes each month?
Serjik [45]

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A. Line graph


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6 0
3 years ago
Read 2 more answers
P PQR=<br><br> - 48<br> - 132<br> - 180
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180. A circle is 360 degrees so half of it would be 180 degrees.
3 0
4 years ago
Read 2 more answers
Differentiate<br>y=tan (x^2-5x+6)​
slavikrds [6]

Use the chain rule:

<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)

<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'

<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that

<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)   →   <em>y(u(x))</em> = tan(<em>u(x)</em> )

By the chain rule,

<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>

and we have

<em>y(u)</em> = tan(<em>u</em>)   →   <em>y'(u)</em> = sec²(<em>u</em>)

<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6   →   <em>u'(x)</em> = 2<em>x</em> - 5

Then

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)

or

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

as we found earlier.

5 0
3 years ago
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