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4 years ago

Find an ordered pair that is a solution to the equation x-4y=4

Mathematics

1 answer:

Oliga [24]4 years ago

8 0

Let be x = - 4; then, - 4 -4y = 4;
-4y = -8 ; y = 2;
An ordered pair that is a solution to the equation is (-4;2);

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Solving polynomial(2y-4)(3y+6)

jeka57 [31]

Answer:

6y² - 24

Step-by-step explanation:

Expand. Follow FOIL method. FOIL =

First

Outside

Inside

Last.

First, multiply the first term of each parenthesis:

2y * 3y = 6y²

Next, multiply the outside terms from both parenthesis:

2y * 6 = 12y

Then, multiply the inside terms from both parenthesis:

-4 * 3y = -12y

Finally, multiply the last terms of each parenthesis:

-4 * 6 = -24

Combine like terms:

6y² + 12y - 12y - 24

6y² + (12y - 12y) - 24

6y² - 24

6y² - 24 is your answer.

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LenaWriter [7]

Answer:

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Which of the following is equivalent to 8/25?

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Question 61 pts Richard has been given a 12-question multiple-choice quiz in his history class. Each question has three answers,

Brut [27]

Answer:

0.946 = 94.6% probability that he will answer at least 2 questions correctly.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

12 questions.

This means that $n = 12$

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This means that $p = \frac{1}{3} = 0.3333$

Assuming that Richard guesses on all 12 questions, find the probability that he will answer at least 2 questions correctly.

Either he answers less than 2 questions correctly, or he answers at least 2 questions correctly. The sum of the probabilities of these outcomes is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$