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larisa86 [58]
3 years ago
11

ERROR204NO FILE AVAILABLE TRY AGAIN LATER

Mathematics
1 answer:
AlekseyPX3 years ago
5 0
Is this a joke or something
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Solve x^2 = 144.<br><br>A. 72 <br>B. 12<br>C. +12<br>D. -12​
Vladimir79 [104]
B. 12

Ex: 12 squared is 144
5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!
Katena32 [7]

Answer:6018

Step-by-step explanation:

Given Sequence

-282-266-250-234.....

It represent an A.P. with

first term a=-282

common difference d=16

So sum of 51 term

S_n=\frac{n}{2}[2a+(n-1)d]

S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]

S_{51}=\frac{51}{2}\times [-564+800]

S_{51}=\frac{51}{2}\times [236]

S_{51}=51\times 118

S_{51}=6018

7 0
3 years ago
Jannie has a budget of $240 to spend on jeans and shirts. She spends $95 on jeans. If the cost of each shirt is $22.50, how many
marysya [2.9K]
240-95=145
145÷22.50=6.44444
OR about 6 shirts
6 0
4 years ago
after a birthday party, 1 4 of a large cake was left. If this piece of cake was shared equally among the 6 people, what fraction
il63 [147K]

The 6 people each got \frac{1}{24}. To get this answer you need to divide the \frac{1}{4} of the cake among 6 people.

Equation ⇒ \frac{1}{4} x \frac{1}{6}

You get the answer by multiplying the bottom denominators.

8 0
3 years ago
Read 2 more answers
If the table shown below represents a function, then which is the possible value for f?
cluponka [151]

Answer:

C 2

Step-by-step explanation:

This is a parabolic function

Notice how we go negative and then positive

y = ax^2 +bx+c

Let x = 0

-5 = a(0) + b(0) +c

c = -5

y = ax^2 + bx -5

Let x = 3

4 = a(3)^2 +b(3) -5

Let x=-3

4 = a(3)^2 -b(3) -5

Add the two equations

4 = a(3)^2 +b(3) -5

4 = a(3)^2 -b(3) -5

----------------------------

8 = 2a (3)^2 - 10

18 = 2 a(9)

18 = 18a

a =1

Solving for b

4 = 1(3)^2 -b(3) -5

4 = 9 -3b -5

4 = 4 -3b

0 = -3b

0 =b

The equation is

y = (x)^2  -5

Letting y = -1

-1 =x^2 -5

Adding 5 to each side

4 = x^2

Taking the square root of each side

±2 = x

x= ±2

Given the choices

5 0
3 years ago
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