Are we assuming there are the same number of students total in both classes for both semesters
1st semester 2 art: 7 gym
2nd semester 5 art: 4 gym so 75 =5/9 75/5=15 for every 1 in the ratio is is = 15 students so 1st semester 30 art 105 gym 2nd semester 75 art 60 gym both have 135 total in both classes both semesters hope i helped -J
There might be two ways to go about this
(1) I am going to assume that we can construct a second (reference) triangle - and you confirmed that it is ok to use trigonometry on that, and then we use the relationship between areas of similar triangles to get what we want. I choose a triangle DEF with same angles, 15, 75, and 90 degrees, and the hypotenuse DE a of length 1 (that is a triangle similar to ABC). I use sin/cos to determine the side lengths: sin(15)=EF and cos(15)=DF and then compute the area(DEF) =EF*DF/2. This turns out to be 1/8 = 0.125.
Now one can use the area formula for similar triangles to figure out the area of ABC - this without trigonometry now: area(ABC)/area(DEF)=(12/1)^2
so area(ABC)=144*area(DEF)=144*0.125=18
(2) Construct the triangle ABC geometrically using compass, protractor, and a ruler. Draw a line segment AB of length 12. Using the compass draw a (Thales') semi-circle centered at the midpoint of AB with radius of 6. Then, using the protractor, draw a line at 75 degrees going from point B. The intersection with the semicircle will give you point C. Finally. draw a line from C to A, completing the triangle. Then, using ruler, measure the length BC and AC.
Calculate the area(ABC)=BC*CA/2, which should come out close to 18, if you drew precisely enough.
Answer: A
Step-by-step explanation:
First you have to calculate the Interest of the loan each month which is 48,000*.05 = 2400/12= 200 dollars he has to pay per month. Then we have have to calculate how much he has to pay off the loan each month which is 48000/5 years to pay it off = 9600/12 months = 800.
800+200= 1000 dollars a month interest and loan
By definition, the area of the trapezoid is:
A = (1/2) * (AB + CD) * (h)
Where,
AB, CD: bases of the trapezoid
h: height
Substituting values:
A = (1/2) * (19 + 19) * (14)
A = 266 units ^ 2
Answer:
The area of the special trapezoid is:
A = 266 units ^ 2
Answer:
it's the 4th one
Step-by-step explanation:
A, the one you mentioned
B, the 7th
C, the 8th
D is your answer