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mart [117]
3 years ago
11

Is 9/3 a repeating decimal? Please answer!!

Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

Step-by-step explanation:

A repeating decimal is a recurring decimal. It has no end when divided.

9/3 is 3 so it is a terminating decimal.

<h2>it does not repeat</h2>
Lynna [10]3 years ago
4 0

Answer:

The single repeating digit is 3.

Step-by-step explanation:

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A movie theater is giving away a souvenir poster to any customer with a concession stand receipt that exceeds $60. The
Doss [256]

Answer:

6x + 3.5y  is greater than 60

Step-by-step explanation:

Cost of x bags of popcorn = 6x

Cost of y bottles of soda = 3.5y

Total cost = 6x + 3.5y

To get a souvenir poster, this cost must exceed 60

6 0
3 years ago
If there are 31,536,000 seconds in one year how many seconds are in a millennium
Naily [24]

A millennium is 1000 years.

Multiply the number of seconds in 1 year by 1000:

31,536,000 x 1,000 = 31,536,000,000 seconds.

5 0
3 years ago
What is <br><br> 6 7/8 c = __ fl oz
masya89 [10]
The answer to this problem is
55 fl oz
6 0
3 years ago
What is the expected average of rolling a single die
larisa86 [58]

Answer:

Mathwords: Expected Value. A quantity equal to the average result of an experiment after a large number of trials. For example, if a fair 6-sided die is rolled, the expected value of the number rolled is 3.5. This is a correct interpretation even though it is impossible to roll a 3.5 on a 6-sided die.

Step-by-step explanation:

hope it helps

5 0
3 years ago
Read 2 more answers
If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th
VMariaS [17]

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

4 0
3 years ago
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