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3 years ago

Write the equation of a horizontal line that passes through the point (-2,2)

1 answer:

5 0

Y=2
If u r finding the equation of horizontal lines it is y=
If u r finding the equation of horizontal lines it is x=
Then just see what point the horizontal or verticals line I passing through, in this case it is positive 2

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A rectangular carpet measures 12m by 5m. Part of the carpet is covered by a square rug of length 2m. What fraction of the carpet

guajiro [1.7K]

Answer:

¹/15

Step-by-step explanation:

Area of the rug = s²

Where s = 2 m

Area of the rug = 2² = 4 m²

Area of the rectangular carpet = length × width

Where,

Length = 12 m

Width = 5 m

Area = 12 × 5 = 60 m²

Fraction of the carpet covered by the rug = area of the rug ÷ area of the carpet = 4/60 = ¹/15

6 0

3 years ago

Which method will NOT get you to the point (4,3.5)?

lesantik [10]

Answer:

A. Starting at the origin, go 3.5 spaces to the right and then 4 spaces up.

Step-by-step explanation:

if you were to plot this then the point would be (3.5,4) instead of (4,3.5)

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3 years ago

If a material absorbs almost all the light waves that reach it, what color will the human eye see?

Lisa [10]

Answer:

what

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the pair of points? (1, 7), (10, 1)

Harrizon [31]

I believe it would be C<span />

4 0

4 years ago

Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain

polet [3.4K]

First we will evaluate: ( substitution: u = x² - y², du = - 2 y dy )
$\int\limits^x_0 {y \sqrt{ x^{2} - y^{2} } } \, dy= \\ \frac{-1}{2} \int\limits^x_0 { u^{1/2} } \, du =$
= $\frac{-1}{3} \sqrt{ (x^{2} - y^{2} ) ^{3} }$ ( than plug in x and 0 )
= $- \frac{1}{3} ( \sqrt{( x^{2} - x^{2}) ^{3} } - \sqrt{ (x^{2} -0 ^{2} ) ^{3} }$ =
= 1/3 x³ ( then another integration )
$1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 ( x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )$
= 1/3 * 1/4 = 1/12

4 0

3 years ago