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3 years ago

Can Someone please help me with this please please please

Mathematics

1 answer:

jasenka [17]3 years ago

4 0

Answer:

About 5.5, but it is technically closer to 5.6 so I am not entirely sure

Step-by-step explanation:

Since EB and DC are parallel, triangles ABE and ACD are similar by AA. Therefore:

$\dfrac{x}{10}=\dfrac{10}{18} \\\\\\x=10\cdot \dfrac{10}{18}\approx 5.5$

Hope this helps!

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Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min. It forms a pile in the shape of a right circular cone whose

Norma-Jean [14]

Answer:

$\frac{dh}{dt}=\frac{160}{169\pi } ft/min$

Step-by-step explanation:

This is a classic related rates problem. Gotta love calculus!

Start out with the formula for the volume of a cone, which is

$V=\frac{1}{3}\pi r^2h$

and with what we know, which is $\frac{dV}{dt}=40$

and the fact that the diameter = height (we will come back to that in a bit).

We need to find $\frac{dh}{dt}$ when h = 13

The thing we need to notice now is that there is no information given to us that involves the radius. It does, however, give us a height. We need to replace the r with something in terms of h. Let's work on that first.

We know that d = h. Because d = 2r, we can say that 2r = h, and solving for r gives us that $r=\frac{h}{2}$ .

Now we can rewrite the formula with that replacement:

$V=\frac{1}{3}\pi (\frac{h}{2})^2h$

Simplify that all the way down to

$V=\frac{1}{12}\pi h^3$

The derivative of that function with respect to time is

$\frac{dV}{dt}=\frac{1}{12}\pi(3h^2)\frac{dh}{dt}$

Filling in what we have gives us this:

$40=\frac{1}{12}\pi (3)(13)^2\frac{dh}{dt}$

Solve that for the rate of change of the height:

$\frac{dh}{dt}=\frac{160}{169\pi } \frac{ft}{min}$

or in decimal form:

$\frac{dh}{dt}=.95\pi \frac{ft}{min}$

8 0

3 years ago

In ΔABC, ∠B measures 35° and the values of a and b are 19 and 11, respectively. Find the remaining measurements of the triangle,

Anna35 [415]

Answer:

a) ∠A = 82.2° , ∠C = 62.8° , c = 17.01

Step-by-step explanation:

Explanation:-

Step(i):-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

By using sine rule

$\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C} = 2 R$

now we will use

$\frac{a}{sin A} = \frac{b}{sin B}$

$\frac{19}{sin A} = \frac{11}{sin 35}$

cross multiplication , we get

$\frac{19 X sin 35}{11} = sinA$

sin A = 0.990

A = sin⁻¹( 0.990) = 82.2°

∠A = 82.2°

Step(ii):-

we know that ∠A +∠B +∠C = 180°

∠C = 180° - ∠A -∠B

∠C = 180° -82.2°-35°

∠C = 62.8°

Step(iii):-

we will use formula

$\frac{b}{sin B} = \frac{c}{Sin C}$

$\frac{11}{sin 35} = \frac{c}{Sin 62.8}$

$\frac{11 X sin (62.8)}{sin 35} = C$

c = 17.01

Final answer:-

∠A = 82.2° , ∠C = 62.8° , c = 17.01

4 0

3 years ago

Madison is baking party favors she wants to make enough favor so each guest gets the same number of favors she knows there will

iris [78.8K]

Answer:

It would be 24

Step-by-step explanation:

6: 6, 12, 18, 24

8: 8, 16, 24

The least common number is 24, so she should make at least 24.

4 0

3 years ago

Please I need help in a rush

baherus [9]

Answer:

i think the answer is 392= 49/Q

3 0

3 years ago

PLS HELP ME ASAP WITH NUMBER 37

Reil [10]

A) The equations are shown on the attached graph.
x = juice box cost
y = water bottle cost

B) Kara's proposed solution satisfies the first equation, but not the second one.

C) The solution is shown on the attached graph.

____
As a bonus, you get a graph for the other problem you posted. Please note this graph has some issues. Wherever there's a solid line ⌝ or ⌞ the actual shape of the graph should be the opposite one of these.

5 0

3 years ago