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krek1111 [17]
2 years ago
5

How to do question five

Mathematics
1 answer:
-BARSIC- [3]2 years ago
8 0
I believe the answer is 46.
Remember "PEMDAS" when doing equations like these :)
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Simplify the equation in simplest for using only positive exponents: (16x^4y^-12)^-5/2?
Lapatulllka [165]

\frac{y^{30} }{1024x^{10} }

Step-by-step explanation:

That is the answer if the equation looks like this:(16x^4y^{-12} )^\frac{-5}{2}

7 0
3 years ago
Angela invested $4000 in an account that earns 5% interest yearly (simple interest). She forgets about it for 12 years. What is
harina [27]

Answer:

$6400

Step-by-step explanation:

4000x.05=200× 12=2400+4000=$6400

4 0
2 years ago
One number is 2 less than a second number. Twice the second number is 5 less than 3 times the first. Find the two numbers.
Evgen [1.6K]

Answer:

9 and 11  

Step-by-step explanation:

First number = x -2

Second number = x

  and   2x = 3(x-2)  - 5

            2x = 3x - 6 - 5

             x = 11

              first number = 11-2 = 9

8 0
2 years ago
ALGEBRA 1 HELP!<br> •GIVING BRAINLIEST!
poizon [28]
20 grams will be left
7 0
3 years ago
A Write an equivalent equation that does NOT contain decimals.
vampirchik [111]

                                                     <span>0.5x - 0.1 = -2.9

When you multiply each side of an equation by the same number,
you don't change the equation or its solution.  If you want to get rid
of the decimals, you could  multiply each side by  10.  Then the
equation is

                                                     5x - 1  =  -29

You should be able to solve that without help.
But I'm about to take your points, so here's
how to solve that equation:

                                            </span><span><span>5x - 1  =  -29

Add  1  to each side:        5x        =  -28

Divide each side by  5 :     x         =  -28 / 5

Simplify the solution:          x         =  -5 and 4/5 .

Again ... this is the same solution as the original equation
if we hadn't gotten rid of the decimals.

</span></span>
5 0
3 years ago
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