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3 years ago

5

How to do question five

1 answer:

-BARSIC- [3]3 years ago

8 0

I believe the answer is 46.
Remember "PEMDAS" when doing equations like these :)

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The average American spent $8,508 on health care in 2011. The cost of health care is projected to rise about 5.8% per year for t

klio [65]

<h3>The projected amount the average American spent on health care in 2014 is $ 10075.91</h3>

<em><u>Solution:</u></em>

Given that,

The average American spent $8,508 on health care in 2011

The cost of health care is projected to rise about 5.8% per year for the years 2012-2022

<em><u>The increasing function is given as:</u></em>

$y = a(1+r)^t$

Where,

y is future value

a is initial value

r is growth rate in decimal

t is number of years

From given,

a = 8508

$r = 5.8 \% = \frac{5.8}{100} = 0.058$

t = 2011 to 2014 = 3 years

<em><u>Substituting the values, we get,</u></em>

$y = 8508(1 + 0.058)^3\\\\y = 8508(1.058)^3\\\\y = 8508 \times 1.1842\\\\y = 10075.914 \approx 10075.91$

Thus the projected amount the average American spent on health care in 2014 is $ 10075.91

4 0

4 years ago

4(3r+2)+3r=-10? help please *confused*

lakkis [162]

$4(3r+2)+3r=-10\\
12r+8+3r=-10\\
15r=-18\\
r=-\frac{18}{15}=-\frac{6}{5}$

3 0

3 years ago

Read 2 more answers

Find all points on the curve x=4cos(t),y=4sin(t) that have the slope of 12.

Marianna [84]

Answer:

$\left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right )$ .

Step-by-step explanation:

We need to find all the points on the curve x=4cos(t),y=4sin(t) that have the slope of 1/2.

$x=4cos (t)$

$\dfrac{dx}{dt}=-4sin (t)$

$y=4sin (t)$

$\dfrac{dy}{dt}=4cos (t)$

Now,

$\dfrac{dy}{dx}=\dfrac{dy}{dt}\times \dfrac{dt}{dx}$

$\dfrac{dy}{dx}=4cos (t)\times \dfrac{1}{-4sin (t)}$

$\dfrac{dy}{dx}=-\cot t$

So, slope of the curve is $-\cot t$ .

$-\cot t=\dfrac{1}{2}$

$-\tan t=2$

$\tan t=-2$ ...(1)

Using $\sec^2t=1+\tan^2t$ , we get

$\sec^2t=1+(-2)^2$

$\sec^2t=1+4$

$\sec t=\pm \sqrt{5}$

$\cos t=\pm \dfrac{1}{\sqrt{5}}$

Now,

$\sin^2t=1-cos^2t$

$\sin t=\pm \sqrt{1-\dfrac{1}{5}}$

$\sin t=\pm \sqrt{\dfrac{4}{5}}$

$\sin t=\pm \dfrac{2}{\sqrt{5}}$

It equation (1), tan(t) is negative. So, sin and cos have different signs.

If $\sin t= \dfrac{2}{\sqrt{5}}$ , then $\cos t=- \dfrac{1}{\sqrt{5}}$ .

$x=4cos (t)=-\dfrac{4}{\sqrt{5}}$

$y=4sin (t)=\dfrac{8}{\sqrt{5}}$

If $\sin t=- \dfrac{2}{\sqrt{5}}$ , then $\cos t= \dfrac{1}{\sqrt{5}}$ .

$x=4cos (t)=\dfrac{4}{\sqrt{5}}$

$y=4sin (t)=-\dfrac{8}{\sqrt{5}}$

Therefore, the two points are $\left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right )$ .

5 0

3 years ago

Me Sidney rented a car for a day. The rental fee consists of flat rate of $19.99 plus 0.21 for an additional mile. For how how m

ipn [44]

19.99+0.21x=52.54

0.21x=32.55

x=155

Mr. Sidney drove 155 miles

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

4 0

4 years ago

What is the pattern 3.5 to 13

mars1129 [50]

Adding 9.5 every time

4 0

3 years ago