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3 years ago

Help me help me help me Help me help me help me

Mathematics

2 answers:

Schach [20]3 years ago

8 0

Answer:B

Step-by-step explanation:

8ab^3/ac^2-14ab^3/ac^2

=-6ab^3/ac2

mars1129 [50]3 years ago

5 0

Answer:the answer is b

Step-by-step explanation:

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7(n+4) ....................

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

$7(n + 4)$

Expand

$7 \times n = 7n \\ 7 \times 4 = 28 \\ \\ 7n + 28$

4 0

3 years ago

What is the Circumference of 2m

Art [367]

Answer:

The circumference of a circle is equal to Pi π times the diameter d

Step-by-step explanation:

3 0

3 years ago

What is the slope of the line that is perpendicular to the line whose equation is 2x+y=4??

zmey [24]

Answer:

The slope would be 1/2

Step-by-step explanation:

y= mx +b

m= slope

perpendicular lines have slopes that are multiplied in order to get -1

<em>these are important</em>

2x + y = 4

<u><em>subtract 2x</em></u>

y=-2x +4

your slope is -2

-2 * ? = -1

? = -1/-2

? = 1/2

6 0

3 years ago

Need help with trig problem in pic

Sidana [21]

Answer:

a) $cos(\alpha)=-\frac{3}{5}\\$

b) $\sin(\beta)= \frac{\sqrt{3} }{2}$

c) $\frac{4+3\sqrt{3} }{10}\\$

d) $\alpha\approx 53.1^o$

Step-by-step explanation:

a) The problem tells us that angle $\alpha$ is in the second quadrant. We know that in that quadrant the cosine is negative.

We can use the Pythagorean identity:

$tan^2(\alpha)+1=sec^2(\alpha)\\(-\frac{4}{3})^2 +1=sec^2(\alpha)\\sec^2(\alpha)=\frac{16}{9} +1\\sec^2(\alpha)=\frac{25}{9} \\sec(\alpha) =+/- \frac{5}{3}\\cos(\alpha)=+/- \frac{3}{5}$

Where we have used that the secant of an angle is the reciprocal of the cos of the angle.

Since we know that the cosine must be negative because the angle is in the second quadrant, then we take the negative answer:

$cos(\alpha)=-\frac{3}{5}$

b) This angle is in the first quadrant (where the sine function is positive. They give us the value of the cosine of the angle, so we can use the Pythagorean identity to find the value of the sine of that angle:

$cos (\beta)=\frac{1}{2} \\\\sin^2(\beta)=1-cos^2(\beta)\\sin^2(\beta)=1-\frac{1}{4} \\\\sin^2(\beta)=\frac{3}{4} \\sin(\beta)=+/- \frac{\sqrt{3} }{2} \\sin(\beta)= \frac{\sqrt{3} }{2}$

where we took the positive value, since we know that the angle is in the first quadrant.

c) We can now find $sin(\alpha -\beta)$ by using the identity:

$sin(\alpha -\beta)=sin(\alpha)\,cos(\beta)-cos(\alpha)\,sin(\beta)\\$

Notice that we need to find $sin(\alpha)$ , which we do via the Pythagorean identity and knowing the value of the cosine found in part a) above:

$sin(\alpha)=\sqrt{1-cos^2(\alpha)} \\sin(\alpha)=\sqrt{1-\frac{9}{25} )} \\sin(\alpha)=\sqrt{\frac{16}{25} )} \\sin(\alpha)=\frac{4}{5}$

Then:

$sin(\alpha -\beta)=\frac{4}{5}\,\frac{1}{2} -(-\frac{3}{5}) \,\frac{\sqrt{3} }{2} \\sin(\alpha -\beta)=\frac{2}{5}+\frac{3\sqrt{3} }{10}=\frac{4+3\sqrt{3} }{10}$

Since $sin(\alpha)=\frac{4}{5}$

then $\alpha=arcsin(\frac{4}{5} )\approx 53.1^o$

4 0

3 years ago

The resale value of a certain car when purchased new is $20,000. The car is expected to lose 10% of its value each year.

UNO [17]

Answer:

The red graph. y intercept is at 20k and is decreasing

3 0

3 years ago