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Ira Lisetskai [31]
3 years ago
6

One number is 17 smaller than another. their sum is 79. find the smaller number

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0
The answer is 62 because sum is addition so you have to subtract 79 from 17
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Need help with this question ! Due soon*
Doss [256]

Answer:

x = 10, AB = 57

Step-by-step explanation:

In a trapezoid, the length of the median is one-half the sum of the lengths of the bases. From this, we have:

\frac{1}{2} (5x + 7 + 8x - 11) = 63

13x - 4 = 126

13x = 130

x = 10

5(10) + 7 = 50 + 7 = 57

5 0
2 years ago
Write an exponential function in the form y=ab^xy=ab
Tcecarenko [31]

Answer:

y = 8 · 10ˣ

Step-by-step explanation:

y = abˣ

When x = 0, y = 8.

8 = ab⁰

8 = a

When x = 3, y = 8000.

8000 = 8b³

1000 = b³

10 = b

The function is:

y = 8 · 10ˣ

3 0
2 years ago
Write 8% as a decimal
viva [34]

Answer:

0.08

Step-by-step explanation:

4 0
2 years ago
What is the scale factor?
muminat

Answer:a scale facter is a scale of how much is one each side or corner and the shape

Step-by-step explanation:

6 0
2 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
2 years ago
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