April plans on starting a perfume business and decides she needs to first

By the definition of a computer, justify if a mobile phone and a calculator are computers or not

likoan [24]

Answer:

It depends on the features of the Calculator but most mobile phones are computers.

Explanation:

A computer is an electronic device that can accept data (Both can), process the data (both can), produce the results of the processed data (both can) and store both result and initial data (some calculators can, some cannot but most mobile phones can).

In my opinion, they are computers but that's dependent on their features especially storage.

3 0

3 years ago

To move the insertion point to another location on the screen, users can use:

Nastasia [14]

By press over the location that you want using mouse

8 0

4 years ago

Read 2 more answers

Consider two decision problems X and Y. If X reduces in polynomial time to 3-SAT and 3-SAT reduces in polynomial time to Y. Whic

tekilochka [14]

Answer:

X is in NP and Y is in NP-HARD ( A )

Explanation:

X is in NP and Y is in NP-HARD can be inferred from the previous statement made in the problem above because problem decision X can be in NP if it can BE reducible to a 3-SAT polynomial real time, if that can be achieved then 3SAT will be in NP since SAT is in NP as well.

also problem decision Y can be in NP-HARD if 3SAT can be reducible to it in polynomial time as well hence option A is the correct option

8 0

3 years ago

Given an array as follows

slava [35]

Answer:

1) Method calcTotal:

public static long calcTotal(long [][] arr2D){
long total = 0;
for(int i = 0; i < arr2D.length; i++ )
{
for(int j = 0; j < arr2D[i].length; j++)
{
total = total + arr2D[i][j];
}
}
return total;
}

Explanation:

Line 1: Define a public method calcTotal and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

public static double calcAverage(long [][] arr2D){
double total = 0;
int count = 0;
for(int i = 0; i < arr2D.length; i++ )
{
for(int j = 0; j < arr2D[i].length; j++)
{
total = total + arr2D[i][j];
count++;
}
}
double average = total / count;
return average;
}

Explanation:

The code in method calcAverage is quite similar to method calcTotal. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

public static double calcRowAverage(long [][] arr2D, int row){
double total = 0;
int count = 0;
for(int i = 0; i < arr2D.length; i++ )
{
if(i == row)
{
for(int j = 0; j < arr2D[i].length; j++)
{
total = total + arr2D[i][j];
count++;
}
}
}
double average = total / count;
return average;
}

Explanation:

By using method calcAverage as a foundation, add one more parameter, row, in the method calcRowAverage. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0

3 years ago

Variance for accumulator. Validate that the following code, which adds the

Art [367]

Using the knowledge of computational language in JAVA it is possible to write a code that Validate that the following code, which adds the methods var() and stddev() to Accumulator, computes both the mean and variance of the numbers presented as arguments to addDataValue()

<h3>Writting the code:</h3>

import java.util.*;

public class Accumulator {

private static double m;

private static double v;

private static double st;

private static double s[]=new double[5];

private static int N;

private static int count =0;

public static void main(String[] args) {

// TODO Auto-generated method stub

Random r = new Random();

System.out.println("hello world");

for(int i=0;i<5;i++) {

double randomvalue = r.nextDouble();

addDataValue(randomvalue);

}

for(int i=0;i<s.length;i++) {

System.out.println("dataValue:"+s[i]);

}

mean();

System.out.println("mean:"+m);

var();

System.out.println("variance:"+v);

stddev();

System.out.println("standard deviation:"+st);

}

public static void addDataValue(double value) { // addes data values to array

s[count]=value;

count++;

}

public static double mean() { // returns mean

double sum=0.0;

for(int i=0;i<s.length;i++) {

sum+=s[i];

}

m = sum/s.length;

return m;

}

public static double var() { //returns variance

double mm = mean();

double t = 0;

for(int i=0;i<s.length;i++) {

t+= (s[i]-mm)*(s[i]-mm);

}

v= t/(s.length-1);

return v;

}

public static double stddev() { // returnsn the stardard deviation

st= Math.sqrt(var());

return st;

}

See more about JAVA at brainly.com/question/12975450

#SPJ1

3 0

1 year ago