We don't want to go to school.

2 answers:

6 0

The correct answer would be
D. No queremos ir a la escuela.

I am fluent in Spanish so if you need any more help in this subject feel free to message me.

pantera1 [17]4 years ago

3 0

D.No queremos ir a la escuela. I hope this helps

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Explanation:

I hope this helps! :)

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Simplify x^3-125/2x-10

MAVERICK [17]

$We \ first, \ simplify \ \frac{125}{2} \\ \\ \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\ pulling \ out \ like \ factors : \\ \\ 2x^3 - 125x = x * (2x^2 - 125) \\ \\ Factoring: \ 2x^2 - 125$

Here's how!

$Proof : \ (A+B) * (A-B) =\\
 A2 - AB + BA - B2 =\\
 A2 - AB + AB - B2 = \\
 A2 - B2\\$

Therefore . . .

$\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }$

The factors would then be the following:

→ $( Leading \ Coefficient : 1,2)$
→ $(Trailing Constant) : 1 ,2 ,4 ,5 ,10 ,20$

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

$\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }}$ ✔

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4 years ago

Are these correct?? Please answer

liraira [26]

Yes this is correct good job

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