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Ede4ka [16]
3 years ago
14

Solve for y=7x-3w for x

Mathematics
1 answer:
il63 [147K]3 years ago
5 0
You would get that X equals 3w over 7 + y over 7<span />
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twenty students in A and 20 students in class B were asked how many hours they took to prepare for an exam.The data sets represe
SSSSS [86.1K]

Answer:

is there a graph i can read?

Step-by-step explanation:

6 0
2 years ago
A naval engineer uses the function, P, to analyze the effects of water pressure on submarines. The function P(d) measures the pr
saw5 [17]

The function that the naval engineer uses related P (pressure) and d (depth of ocean).

<em>Is there any restriction on the domain ( d: depth of the ocean)? Yes!</em>

The domain would be from 0 (at sea level or 0 depth) until the depth of the ocean (which is not infinite). Hence, we can write:

0\leq d\leq DepthOfSeaFloor

Choice D is the correct one.


ANSWER: D

5 0
3 years ago
Read 2 more answers
The length of a rectangle is four more than triple the width. if the perimeter is 120 inches, find the dimensions.
mezya [45]
120/2=60 (sum of both lengths)
4x+4=60
4x=56
x=14

length=46
width=14
5 0
2 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
3 years ago
For the following geometric sequence find the explict formula -1 ,3, -9.
Afina-wow [57]

Answer:

-1 x -3^{n-1}

Hope this helps

Step-by-step explanation:

5 0
3 years ago
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