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3 years ago

Solve the equation. −t\4=−3π

2 answers:

8 0

If you want to estimate π, the answer would be:
-t/4=-3(3.14)
-t=-9.42*4
-t=37.68
t=-37.68

Otherwise, the answer is 12π

vampirchik [111]3 years ago

7 0

we have

$-\frac{t}{4} =-3\pi$

solve for t

Multiply by $-4$ both sides

$-\frac{t}{4}*(-4) =-3\pi*(-4)$

$t=12\pi$

therefore

<u>the answer is</u>

$t=12\pi$

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An experiment is set up to study the weights of 35 mice after they are injected with a drug. The population mean is 23.50 grams

IgorC [24]

Answer:

The standard error of the sample mean is 0.57

Step-by-step explanation:

we know that

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$SE = \frac{s}{ \sqrt{n} }}$

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In this problem we have

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3 years ago

90sec equal to how many min

Kruka [31]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

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inn [45]

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3 years ago

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Using inconsistent intervals along the y-axis can cause a graph to be misleading. True or false

spayn [35]

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3 years ago

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The coordinates of a quadrilateral are (1,3), (7,-3), (1,-9), and (-5,-3). What shape is formed? Select all that apply. -Kite -R

chubhunter [2.5K]

Answer: Sqaure

Step-by-step explanation:

We obtain the figure by either plotting or finding the distances between the points:

$\begin{aligned}&\text { Distance } b / w \quad A B =\sqrt{(1-7)^{2}+(3-(-3))^{2}}\\&=\sqrt{6^{2}+6^{2}}\\&A B=\sqrt{72} \text { units }\end{aligned}$

$\text { Distance } b / w \quad BC =\sqrt{(7-1)^{2}+(-3-(-9))^{2}} \\BC=\sqrt{72} \text { units }$

$\begin{aligned}\text { Distance } b / w \ C D &=\sqrt{(1-(-5))^{2}+(-9-(-3))^{2}} \\C D=\sqrt{72} \text { units }\end{aligned}$

$$$ Distance $b/w \ A D=\sqrt{(1-(-5))^{2}+(3(-3))^{2}}$A D=\sqrt{72} \text { units }$

Since all the distances of the four sides are equal, we have to check if the shape is either a rhombus or a square by the measuring the length of the diagonals

$\begin{aligned}A C &=\sqrt{(1-1)^{2}+(3-(-9))^{2}} \\&=\sqrt{12^{2}} \\A C &=12 \text { units } \\B D &=\sqrt{(7-(-5))^{2}+(-3-(-3))^{2}} \\&=\sqrt{12^{2}} \\A C &=12 \text { units }\end{aligned}$

The diagonals are also equal; therefore, the figure is a square

7 0

2 years ago