Answer: youre so right.
Step-by-step explanation:
you=100%
You multiply the number then divide by 2 or just keep it the same answer
since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Answer:
(0,-3) will give the maximum value
Step-by-step explanation:
To know the vertex, we have to substitute the coordinates in the options
we have this as follows
a) (1.5,0)
T = 1.5-3(0) = -1.5
b) (3.5,4)
T = 3.5 - 1)4)
= 3.5 - 4 = -0.5
c) (0,-3)
we have
T = 0-3(-3) = 0 + 9 = 9
d) (0,4)
we have this as:
T = 0 - 3(4) = -12