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3 years ago

What is the multiplicative inverse of 9/15

Mathematics

2 answers:

marusya05 [52]3 years ago

7 0

Answer:

$\frac{15}{9}$

Step-by-step explanation:

The multiplicative inverse of a number n is $\frac{1}{n}$

Given

$\frac{9}{15}$ then the multiplicative inverse is

$\frac{1}{\frac{9}{15} }$ = $\frac{15}{9}$

Elenna [48]3 years ago

3 0

Answer:

5 and 3

Step-by-step explanation:

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3 years ago

Read 2 more answers

A carnival game involves drawing a card from a deck of 40 cards, replacing it, shuffling the deck, and drawing another

padilas [110]

Answer:

4 tokens.

Step-by-step explanation:

The expected value of a given event is calculated as:

EV = (x₁*p₁ + x₂*p2 + ... + xₙ*pₙ)

Where xₙ is the n-th outcome, and pₙ is its probability.

In this case, our experiment is:

You draw two times.

We have 30 cards with no prize

We have 10 cards with a prize.

A total of 40 cards.

As we draw two times (and the first time we draw a card we put it back in the deck) we can consider the events as independent, so we can find the expected value per draw.

Now we can define:

x₁ = drawing a blank card = 0 tokens

The probability will be equal to the quotient between the number of blank cards and the total number of cards

p₁ = 30/40 = 3/4

x₂ = drawing a prized card = 8 tokens.

The probability will be equal to the quotient between the number of prized cards and the total number of cards:

p₂ = 10/40 = 1/4

Then the expected value per draw is:

EV = ( (3/4)*0 tokens + (1/4)* 8 tokens) = 2 tokens.

And we have two draws, then the expected value of two draws is two times the expected value per draw, this means that the expected value in our case is:

expected value = 2*(2 tokens) = 4 tokens.

The correct option is the first one, counting from the top.

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3 years ago

A baseball team has 4 pitchers, who only pitch, and 16 other players, all of whom can play any position other than pitcher. F

ivolga24 [154]

Answer:

2,075,673,600 batting orders may occur.

Step-by-step explanation:

The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

First 8 batters

8 players from a set of 16. So

$P_{(16,8)} = \frac{16!}{(16 - 8)!} = 518918400$

Last batter:

Any of the four pitchers.

How many different batting orders may occur?

4*518918400 = 2,075,673,600

2,075,673,600 batting orders may occur.

5 0

4 years ago