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Trava [24]
3 years ago
9

What number can go into 4 and 33​

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

Step-by-step explanation:

1 my dude

kati45 [8]3 years ago
8 0

Answer:132

Step-by-step explanation: you just need to find their L.C.M

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PLZ 29 POINTS FOR FIRST RIGHT ANSWER AND BRAINLEST AND 5 STAR AND THANKS NEED ASAPPPPP LIKE LESS THAN 10 MINS
AlladinOne [14]

Answer:

c

Step-by-step explanation:

When you are find a percentage of a number you must first turn the percent into a number so firstly turn 10% into .10

then take and turn it into a fraction which equals 10/100 x 275 so ur answer is c

5 0
3 years ago
The area of a square patio is 49^3 square inches. find the length of one side of the patio. Please show work.
Hatshy [7]
A = l × w
So, first you solve 49^3 and get 117,649 square inches. Then you divide that by 2 and get 58,824.5, because 58,824.5 × 2 is 117,649.

Your answer is: one patio side length is 58,824.5 inches long
3 0
3 years ago
Read 2 more answers
90 POINTS!!! PLEASEE HELP AND SHOW WORK. I WILL GIVE BRAINLIEST IF ALL WORK IS SHOWN THANKSS.
konstantin123 [22]

Answer:

18. 3.3years

Step-by-step explanation:

18. 20,000 - (20,000 - .15x) = 10,000

15% of 20,000 is 3,000

5 0
3 years ago
If a store sold 25 pairs of socks, making a 25% profit (i.e., percent of sales) of $150, how much did they charge for each pair
yKpoI14uk [10]

Answer:

125

Step-by-step explanation:

150 - 25 = 125  ;)

5 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
3 years ago
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