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Firdavs [7]
4 years ago
9

Solve for j : CE/2 =3jq/7

Mathematics
2 answers:
nekit [7.7K]4 years ago
7 0

\dfrac{CE}{2}=\dfrac{3jq}{7}\\ 6jq=7CE\\ j=\dfrac{7CE}{6q}

zalisa [80]4 years ago
6 0

<u>Answer</u>

J= \frac{7CE}{6q}


<u>Detailed Explanation </u>

First, let's set up a proportion.

\frac{CE}{2} = \frac{3jq}{7}


Now, solve.

7CE=6jq


J= \frac{7CE}{6q}


Therefore, the answer would be J= \frac{7CE}{6q}



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Step-by-step explanation:

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Subtract 17 from each side

x+ 17 -17≤-3-17

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9) Gabe has a 40¢-off coupon for any kind of popcorn. He can choose
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Answer:

Per ounce better buy is <em>Happy popcorn</em>.

Step-by-step explanation:

Given that:

Happy popcorn price for 16 ounces = $1.39

Popper popcorn price for 34 ounces = $2.79

Discount coupon present with Gabe = 40 ¢ = $0.40

To find:

Which brand is the better buy per ounce?

Solution:

First of all, let us calculate the price that Gabe has to pay after the discount coupon being applied.

Price for 16 ounces of Happy popcorn after discount = $1.29 - $0.40 = $0.99

Price for 1 ounce of Happy popcorn after discount = \frac{\$0.99}{16} = $0.062

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Price for 1 ounce of Popper popcorn after discount = \frac{\$2.39}{34} = $0.070

Clearly, per ounce price of Happy popcorn is lesser than that of Popper popcorn.

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3 years ago
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4 years ago
Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
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<u>SOLUTION :-</u>

In the triangle on the right side ,

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∴ x = 30m

3 0
3 years ago
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