Due to the fact that 43 is prime number, meaning that no other number can go into it besides 1 and itself.
Is already in simplest form.
Hope this helps!=)
I am assuming you meant "Roll a sum of 10".
First find all the combinations:
1st dice 2nd dice
4 + 6
5 + 5
6 + 4
Next, calculate the probability of rolling a 4,5, or 6: 3/6 => 1/2 on first dice
Then, calculate the probability of rolling a number on the second dice that adds up with the first number to make 10.
Note: once you roll the first number only 1 other number will make a match, so the probability on the second dice is: 1/6 on second dice
Finally, multiply the two fractions together: 1/2 x 1/6 = 1/12
Your probability is: 1/12 in fraction form, .083 in decimal form, and 8.33% in percent form.
Hope this helps and May the Force Be With You!
-Jabba
The answer is B because $5.12 was removed from the total she had
Answer:
f(5) = -11
Step-by-step explanation:
f(5) = (-3(5) - 6) + 10
f(5) = -21 + 10
f(5) = -11
Domain is numbers you can use
we can't use numbers that cause problems
numbers that make division by zero and sqar roots of negative numbers
f(x)=√x+2
x cannot be negative
x can equal zero, that results in zero
√0=0
domain=all real numbers greater than or equal to 0
C