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Jet001 [13]
3 years ago
13

How is this ejercise: 81x= 9

Mathematics
2 answers:
vaieri [72.5K]3 years ago
4 0
81x=9  divide both sides by 9 and will get 

9x=1 divide both sides by 9 and will get 

x = 1/9 

hope helped 
Sever21 [200]3 years ago
3 0
81x=9/:9
9x=1
x=1/9
Hope I helped
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b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ e
PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

Hello!

<em>Full text</em>

<em>In a national survey college students were​ asked, "How often do you  wear a seat belt when riding in a car driven by someone​ else?" The response frequencies appear in the table to the right.​ (a) Construct a probability model for​ seat-belt use by a passenger.​ (b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else? </em>

<em>Response , Frequency   </em>

<em>Never  102 </em>

<em>Rarely  319 </em>

<em>Sometimes  524 </em>

<em>Most of the time  1067 </em>

<em>Always  2727 </em>

n= 102+319+524+1067+2727= 4739

<em> ​(a) Complete the table below. </em>

<em>Response </em>

<em>Probability  </em>To calculate the probability for each response you have to divide the frequency of each category by the total of people surveyed:

<em>Never </em> P(N)= 102/4739= 0.0215

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Rarely </em> P(R)= 319/4739= 0.0673

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Sometimes </em> P(S)= 524/4739= 0.1106

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Most of the time  </em>P(M)= 1067/4739= 0.2252

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Always  </em>P(A)= 2727/4739= 0.5754

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em />

<em>​(b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else? </em>

<em>A. </em>

<em>​No, because there were 102  people in the survey who said they never wear their seat belt. </em> Incorrect, an event is considered unusual if its probability (relative frequency) is low, you cannot know if it is usual or unusual just by looking at the absolute frequency of it.

<em>B. </em>

<em>​Yes, because ​P(never) < 0.05. </em> Correct

<em> C. </em>

<em>​No, because the probability of an unusual event is 0.    </em>Incorrect, the probability of unusual events is low, impossible events are the ones with probability zero

<em>D. </em>

<em>​Yes, because 0.01 < ​P(never) <  0.10. </em>Incorrect, by the definition an event is considered unusual when its probability is equal or less than 5%.

I hope this helps!

3 0
3 years ago
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