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3 years ago

V=3.14r^2h solve for h

2 answers:

5 0

$v=3.14r^2h$

$\dfrac{v}{3.14} =r^2h$ $Divide \ both \ sides \ by \ 3.14$

$\dfrac{v}{3.14r^2} =h$ <span> $Divide \ both \ sides \ by \ r^2$ </span>

taurus [48]3 years ago

4 0

$V=3.14r^2h\ \ \ \ \ |divide\ both\ sides\ by\ 3.14r^2\\\\\boxed{h=\dfrac{V}{3.14r^2}}$

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I need the answer because I can’t i need help

Free_Kalibri [48]

Answer:

3 $\frac{3}{4}$ , 4 $\frac{1}{4}$ , 4 $\frac{1}{2}$ (two x's on this spot), 5

Step-by-step explanation:

you need an x in each point (A, B, C, D, E) given in the chart

notice point B and E are the same

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2 years ago

3(7x+2)+6x plz answer

Natalija [7]

Answer:

27x +6

Step-by-step explanation:

3(7x+2)+6x

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4 0

3 years ago

Read 2 more answers

A new lawn has a perimeter of 278ft. And a width of 64ft. A bag of grass seed will cover 384ft of ground. How many bags of grass

Anit [1.1K]

Answer:

13 bags

Step-by-step explanation:

Area of the lawn: A=lw

w= 64 ft

P= 2(l+w)= 278 ft ⇒

l= 278/2- 64= 75 ft

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bags of seed required:

4800/384= 12.5 so 13 full bags needed

7 0

3 years ago

gavin and marco each have equal sized pieces of rope. gavin uses 1/4 of his rope for an art project. marco uses 1/8 of his rope

marissa [1.9K]

Answer:

Gavin uses more rope.

Step-by-step explanation:

Because 1/4>1/8, since 1/4=0.25 and 1/8=0.125.

5 0

3 years ago

The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di

Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x P(x) xP(x) x² x²P(x)

0 0.25 0 0 0

1 0.20 0.20 1 0.20

2 0.15 0.3 4 0.6

3 0.30 0.9 9 2.7

4 0.10 0.4 16 1.6

∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

$\sum P(X)=0.25+0.20+0.15+0.30+0.10$

$\sum P(X)=1$

Yes it is a probability distribution.

b) The expected value of x is defined as

$E(x)=\sum xP(x)=1.8$

c) The variance of x is defined as

$V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86$

d) The standard deviation of x is defined as

$\sigma=\sqrt{V}$

$\sigma=\sqrt{1.86}$

$\sigma=1.136$

5 0

2 years ago