A line passes through the points (-4,-1) and (-2,-4) fill in the blanks to complete an equation for the line in point slope form

inna [77]

<h3>Answer: D. (2, 21)</h3>

Explanation:

Imagine that your teacher wanted you to find the midpoint of -3 and 7 on the number line. To do this, you would add up the given values and divide by 2.

(-3+7)/2 = 4/2 = 2

The value 2 is right in the middle of -3 and 7 on the number line. This result is also the x coordinate of the midpoint since the values I used were the x coordinates of the original points.

The y coordinates are handled the same way:

(18+24)/2 = 42/2 = 21

The y coordinate of the midpoint is y = 21

Overall, the midpoint is (2, 21)

3 0

2 years ago

Read 2 more answers

What is 1/2 divided by 1/6?

Contact [7]

Answer:

1. How many times can 0.17 be multiplied to equal 0.50?

2. 3

Step-by-step explanation:

To solve this problem, let's turn these decimals into fractions.

1/2 = 0.50

1/6 = 0.17

Now, we must ask ourselves: How many times can 0.17 be multiplied to equal 0.50?

0.50 = 3 when divided by the nearest whole number.

Therefore, the answer is 3.

Hope this helps! :D

6 0

3 years ago

How does finding the square root of a number compare to finding the cube root of a number. Use the number 64 in your explanation

andre [41]

If $x^2=y$ , then $\sqrt[2]{y}=\sqrt[2]{x^2}=x$

if $x^3=y$ , then $\sqrt[3]{y}=\sqrt[3]{x^3}=x$

ok
$64=8^2=4^3$

so
$\sqrt[2]{64}=\sqrt[2]{8^2}=8$
$\sqrt[3]{64}=\sqrt[3]{4^3}=4$

well, the cube root usually bigger

7 0

3 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

4 years ago

Simplify this radical.

Lunna [17]

Answer:

D

Step-by-step explanation:

did it on edge

7 0

3 years ago

Read 2 more answers