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Readme [11.4K]
3 years ago
9

If I have 10 dollars and I win 6 out of 10 and lose 4 out of 10 and bet 1$ each trade, how much should there be left after 10 tr

ades?
Mathematics
1 answer:
ololo11 [35]3 years ago
7 0

you will be left with 12 dollars.

<u> </u><u>Step-by-step explanation: </u>

Given:

The actual money you have = 10 dollars.

The bet amount for each trade= 1$

For each win, you get extra +1 dollar.

Step 1:

So, you won 6 trades= (6*1)= 6$

Step 2:

For each lose, you loss -1 dollar.

Step 3:

So, you lose 4 trades= (4)*(-1)= -4$

Step 4:

After 10 trades, the money you earned is= 6$ -4$= 2 dollars.

Finally, the total money left after 10 trades is= actual money + earned money                                                

= $10 + $2= 12 dollars.

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Answer:

Alex is reading faster by 5 more pages per hour.

Step-by-step explanation:

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Answer:

x=-1\\y=-1

Step-by-step explanation:

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Let's solve the first equation for either x or y. I'll do it for x.

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Begin by subtracting 5y.

5x=-5y-10

Now divide by 5.

x=\frac{-5y}{5}-\frac{10}{5}

Simplify:

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Now substitute x in the second equation for this value.

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Distribute;

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Add 6

-3y-7y=4+6

Combine like terms;

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Divide by -10.

y=\frac{10}{-10}\\ y=-1

-----------------------------------------------------------------------------------------------------------

Take this value of y and replace it in the first equation to find the value of x.

5x+5y=-10\\5x+5(-1)=-10\\5x-5=-10\\5x=-10+5\\5x=-5\\x=\frac{-5}{5}\\ x=-1

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