Question

What is the equation of the trend line? Enter your answers in the boxes. K = J + Scatter plot on a first quadrant coordinate grid. The horizontal axis is labeled Variable J. The vertical axis is labeled Variable K. Points are plotted at (two, sixteen), (two, twenty four), (four, sixteen), (four, twenty), (five and ninety-three hundredths, nine and sixty-two hundredths), (six, twelve), (six, sixteen), (ten, zero), (ten, two), (ten, eight). A line is drawn through (four, sixteen) and (six, twelve).

Answer 1

that guy put the wrong answer btw

Answer 2

Answer:

Step-by-step explanation:

Given that the horizontal axis is labeled with J. The vertical axis is labeled with Variable K. Points are plotted at (2,16), (2,24), (4,16), (4,20), (5,9300), (9,6200), (6,12), (6,16), (10,0), (10,2), (10,8).

Also line drawn through points (4,16) and (6,12).

The equation of scatter line

$y-y'=\frac{y_2-y_1}{x_2-x_1}(x-x')$

⇒ $y-12=\frac{12-16}{6-4}(x-6)$

⇒ $y-12=-2(x-6)$

⇒ $y=-2x+24$

Now, we can replace x as J and y as K, we get the equation of scatter plot on first quadrant which can be written as

K=-2J+24 ⇒ K+2J-24=0