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Rom4ik [11]
3 years ago
13

Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0

We are given the function:

g(x) = 6 (4)^x

 

Part A.

To get the average rate of change, we use the formula:

average rate of change = [g(x2) – g(x1)] / (x2 – x1)

 

Section A:

average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) = 18

 

Section B:

average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) = 288

 

Part B.

288 / 18 = 16

Therefore the average rate of change of Section B is 16 times greater than in Section A.

 

<span>The average rate of change is greater between x = 2 to x = 3 than between x = 1 and x = 0 because an exponential function's rate of change increases with increasing x (not constant).</span>

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Answer:

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Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

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Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

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