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stepan [7]
3 years ago
15

What is the variable

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
A quantity that may change
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http://www.purplemath.com/modules/specfact.htm

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MayaKay and Alyssa work in the returns department for an online company. MayaKay can process 24 returns in 3 hours. Alyssa takes
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I think its Alyssa

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they both can process 8, but it took Mayakay 3 hours to process 24 and it took Alyssa 5 hours to process 40, so even though Alyssa time is longer she processed more

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Omar drove 249 kilometers in 3 hours he drove at a constant speed how many kilometers did he drive in 1 hour?
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Explain why a trapezoid can't be called a parallelogram
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3 years ago
Read 2 more answers
A design for party favors are in the shape of a regular hexagonal pyramid. The hexagon has a side length of 6 inches. The latera
Nookie1986 [14]

Answer:

Part 1) LA=108\sqrt{2}\ in^2

Part 2) B=54\sqrt{3}\ in^2

Step-by-step explanation:

Part 1) Find the lateral area of the pyramid

we know that

The lateral area of the pyramid, is equal to the area of six congruent isosceles triangles

so

LA=6[\frac{1}{2}(b)(h)]

we have

b=6\ in

Applying Pythagorean Theorem calculate the height of triangle

9^2=(6/2)^2+h^2

h^2=81-9\\h^2=72\\h=\sqrt{72}\ in

simplify

h=6\sqrt{2}\ in

Find the lateral area

LA=6[\frac{1}{2}(6)(6\sqrt{2})]\\\\LA=108\sqrt{2}\ in^2

Part 2) Find the base area

we know that

The area of a regular hexagon is equal to the area of six equilateral triangles

so

Applying the law of sines to calculate the area of triangle

B=6[\frac{1}{2}b^2sin(60^o)]

we have

b=6\ in

sin(60^o)=\frac{\sqrt{3}}{2}

substitute

B=6[\frac{1}{2}6^2(\frac{\sqrt{3}}{2})]

B=54\sqrt{3}\ in^2

3 0
4 years ago
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