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lozanna [386]
3 years ago
14

How did Dr.Tierno find the answer to his question ?

SAT
2 answers:
nydimaria [60]3 years ago
4 0
What is this referring to?
Darina [25.2K]3 years ago
3 0
Sorry? What was his question?
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your business plan calls for sales of $45,000 in year 1 with compound growth of 30% per year thereafter. what are your projected
RSB [31]

Answer:

48000

Explanation:

because,

45000×(1+30×100)

7 0
2 years ago
Define a pattern of art
DedPeter [7]

Answer:

In art, a pattern is a repetition of specific visual elements.

Explanation:

7 0
3 years ago
A photographic stop bath contains 160ml of pure acetic acid.
NeTakaya

Answer:

Solving for the Percent by Volume

The v/v concentration of acetic acid in the stop bath is 24.6%.

Explanation:

To answer the question, we need to identify certain information stated in the question. Let us write down what’s given:

Volume of solute = 160 mL

Volume of solution = 650 mL

Next, we need to determine what is required, in this case, the percent by volume. Now, let us look at the formula:

v/v concentration = (solute volume / volume of the solution) * 100

Solution:

Percent by Volume = (160 / 650) * 100

Percent by Volume = 0.2461538461538462 * 100

Percent by Volume = 24.61538461538462

Rounded off = 24.6%

Therefore, the final answer is 24.6%

Explanation:

7 0
2 years ago
Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

  • T_{s} - Final temperature, in degrees Celsius.
  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
  • T(t) - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

\frac{60-50}{80-50}= e^{-15\cdot k}

\frac{1}{3} = e^{-15\cdot k}

k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

7 0
2 years ago
Plz can you add enough word to = 350
Salsk061 [2.6K]

Answer: ok

Explanation:

3 0
3 years ago
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