3 years ago

If cos 0 = -4/9 with 0 in Quadrant II, find sin 0

1 answer:

4 0

Sin0= y/r

X= -4 and r= 9 (radius is also the hypotenuse)
In quadrant II y is positive
X^2 +y^2 = r^2

-4^2 + y^2 = 9^2
16 + y^2 = 81
Y^2 = 81-16
Y^2 = 65
Y= sqrt65

Sin0= sqrt65/9

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