Studying animals in the wild is considered somewhat experimentally out of control because of several reasons.
<u>Explanation:</u>
Study of wild animals can be done using several methods but none will be as effective as studying captivated animals. Using stationary cameras is a method to observe animals in the wild. The stationary nature of the camera makes it necessary for the animals to appear within the field of the camera.
This is difficult in places of low animal density. In addition to that placing camera at a longer distance to watch a larger area decreases the resolution of the images. When it comes to shallow water systems, the field imagery used to track the aquatic species frequently gets affected by issues like sun flicker.
Unmanned aerial vehicles can also be used to track and study animals in the wild. This is good alternative but filming through dense canopies or turbid water is a limitation. Bio loggers can also be used for animal tracking but it is limited by weight since it has to be carried by animals.
Answer:
OC
Explanation:
Primary succession begins after a new habitat is opened that was previously unavailable- for example, lava flow that left behind bare rock. This successions normally begins with organisms like lichens, which are able to survive in these conditions. It has no soil and was previously uninhabited.
Secondary succession begins as a response to a disturbance that clears a previously inhabited area, like a forest fire or tsunami. This may cause a lot of destruction and death, but afterwards there is still soil available for new plants to grow again. Eventually, the habitat will regrow itself.
Answer:
Explained
Explanation:
Due to lack of of Triose phosphate isomerase cell will be unable to interconvert Dihydroxyacetone to glyceraldehyde 3 phosphate.
And the cells will be able to complete the glycolysis only in the presence of glyceraldehyde 3 phosphate which will generate 2 ATP and hence the net ATP gain during whole process in anaerobic condition will be Zero. This will lead to the dath of the mutant yeast.
a) While in case of aerobic condition, only one molecule of pyruvate will also be able to produce more ATP compared to anaerobic condition by further oxidation which is sufficient for yeast to survive.
b) the cells will be able to complete the glycolysis only in the presence of glyceraldehyde 3 phosphate which will generate 2 ATP and hence the net ATP gain during whole process in anaerobic condition will be Zero. This will lead to the death of the mutant yeast.
Epithelial tissue covers the body, lins internal surfaces, and forms glands.
I believe its 75% or 50% definetly use a punnet square to check tho!