Answer:
5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .
Step-by-step explanation:
As given
Amy and Mary are playing a board game that uses game money if $5 and $10.
At the end of the game, Amy has n bills worth $5 each and d bills worth $10 each .
Total amount of n bills = 5n
Total amount of d bills = 10d
Thus
Total money spend by the Amy in playing board games = Total amount of n bills + Total amount of d bills
= 5n + 10d
Therefore 5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .
7 and 2 cannot be the lengths as on a triangle they're two equal side so two 3s or two 5s
Answer:



Step-by-step explanation:
Given
--- 8 friends
--- proportion that one-time fling
This question is an illustration of binomial probability, and it is represented as:

Solving (a): P(x = 0) --- None has done one time fling




Solving (b): 
To do this, we make use of compliment rule:

Rewrite as:



Solving (c):
--- Not more than 2 has one time fling
This is calculated as:

We have:







So:



A line which represents the line of best fit is: C. Line B.
<h3>What is a line of best fit?</h3>
A line of best fit is sometimes referred to as a trend line and it can be defined as a statistical or analytical tool that is commonly used in conjunction with a scatter plot, in order to determine whether or not there is any form of association and correlation between a data set.
<h3>The characteristics of a line of best fit.</h3>
In Mathematics, there are different characteristics that are used for determining the line of best fit on a scatter plot and these include the following:
- The line should be very close to the data points as much as possible.
- The number of data points that are above the line should be equal to the number of data points that are below the line.
By critically observing the scatter plot using the aforementioned characteristics, we can reasonably and logically deduce that line B represents the line of best fit because the data points are in a linear pattern.
Read more on line of best fit here: brainly.com/question/12284501
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