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4 years ago

________ is the set of instructions that programmers have written in a higher-level language. select one:

1 answer:

6 0

The answer is a. Source Code. It is the set of instructions that programmers have written in a higher-level language. When a programmer types a sequence of C language<span> statements into Windows Notepad, for example, and saves the sequence as a text file, the text file is said to contain the source code. </span>

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Because __________ software can block suspicious software in real-time, it has an advantage over such established anti-virus det

shutvik [7]

Because dynamic analysis software can block suspicious software in real-time, it has an advantage over such established anti-virus detection techniques as fingerprinting or heuristics.

<h3>What is dynamic program analysis?</h3>

The examination of computer software by means of the execution of programs on a physical or virtual processor is known as dynamic program analysis.
Effective dynamic program analysis requires running the target program with enough test inputs to account for almost all potential outputs.
Utilizing software testing tools like code coverage increases the likelihood that a sufficient sampling of the program's potential behaviors has been seen.
Additionally, it is important to take precautions to reduce the impact that instrumentation has on the target program's execution, especially its temporal characteristics.
Static program analysis contrasts with dynamic analysis. Dynamic testing is used in unit tests, integration tests, system tests, and acceptance tests.

To learn more about the topic, refer to the following link:

brainly.com/question/17209742

#SPJ4

8 0

2 years ago

Initialize an int variable named as sum to 0. Write the while loop that lets the user enter a number. The number should be added

FromTheMoon [43]

Answer:

Following are the program to this question:

#include<iostream> //defining header file

using namespace std;

int main() //defining main method

{

int sum = 0, num; //defining integer variable

cout << "Enter a number :"; // print message

cin >> num; //input number

sum=sum+num;

while (sum < 200) //defining loop that check sum value is less then 200

{

cin >> num; //input number by user

sum =sum+num; //add values

}

cout << "Sum = " << sum <<" the loop stops"; //print values

return 0;

}

output:

Enter a number :44

Sum = 200 the loop stops

Explanation:

In the given C++ program, the main method is declared, inside the method two integer variable "sum and num" is declared, in which sum variable assign a value, that is 0, and num is used to take input from the user end.

In the next step, a sum variable adds num variable value and use a while loop that checks value is less than 200.
In this condition is not true so, inside the loop, it takes value from the user and into the sum variable when its value is above 200, it will exit the loop and prints its total value.

8 0

4 years ago

Suppose list1 is an MyArrayList and list2 is a MyLinkedList. Both contains 1 million double values. Analyze the following code:

hjlf

Answer:

The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".

Explanation:

In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below

(A.) The Code fragment A runs fastly than the code fragment of B.

(B.) The Code fragment B runs fastly than code fragment of A.

So we conclude the answer i.e option(A) because As given in the question list1 is a MyArrayList and list2 is a MyLinkedList. , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.

The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then MyArrayList is a better option so the code fragment runs fastly then code fragmented B.

7 0

4 years ago

A spreadsheet program is a computerized version of

IRISSAK [1]

Graph paper pretty much

3 0

3 years ago

Read 2 more answers

Write Album's PrintSongsShorterThan() to print all the songs from the album shorter than the value of the parameter songDuration

Romashka-Z-Leto [24]

Answer:

Here is the function PrintSongsShorterThan() which prints all the songs from the album shorter than the value of the parameter songDuration.

void Album::PrintSongsShorterThan(int songDuration) const {

unsigned int i;

Song currSong;

cout << "Songs shorter than " << songDuration << " seconds:" << endl;

for(int i=0; i<albumSongs.size(); i++){

currSong = albumSongs.at(i);

if(currSong.GetDuration()<songDuration){

currSong.PrintSong(); } } }

Explanation:

I will explain the working of the for loop in the above function.

The loop has a variable i that is initialized to 0. The loop continues to execute until the value of i exceeds the albumSongs vector size. The albumSongs is a Song type vector and vector works just like a dynamic array to store sequences.

At each iteration the for loop checks if the value of i is less than the size of albumSongs. If it is true then the statement inside the loop body execute. The at() is a vector function that is used to return a reference to the element at i-th position in the albumSongs. So the album song at the i-th index of albumSongs is assigned to the currSong. This currSong works as an instance. Next the if condition checks if that album song's duration is less than the specified value of songDuration. Here the method GetDuration() is used to return the value of duration of the song. If this condition evaluates to true then the printSong method is called using currSong object. The printSong() method has a statement cout << name << " - " << duration << endl; which prints/displays the name of the song with its duration.

If you see the main() function statement: musicAlbum.PrintSongsShorterThan(210);

The musicAlbum is the Album object to access the PrintSongsShorterThan(210) The value passed to this method is 210 which means this is the value of the songDuration.

As we know that the parameter of PrintSongsShorterThan method is songDuration. So the duration of each song in albumSongs vector is checked by this function and if the song duration is less than 210 then the name of the song along with its duration is displayed on the output screen.

For example if the album name is Anonymous and the songs name along with their duration are:

ABC 400

XYZ 123

CDE 300

GHI 200

KLM 100

Then the above program displays the following output when the user types "quit" after entering the above information.

Anonymous

Songs shorter than 210 seconds:

XYZ - 123

GHI - 200

KLM - 100

Notice that the song name ABC and CDE are not displayed because they exceed the songDuration i.e. 210.

The output is attached.

3 0

3 years ago